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Sliva [168]
3 years ago
7

Formula for face diagonal?

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

Face diagonal of a cube:

Step-by-step explanation:

f2 = a2 + a. Then f2 = 2a.

anygoal [31]3 years ago
7 0
Face diagonal = √(a² + a²) = √2a² = a√2 - it's our cube face diagonal
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Describe a capricormus constellation ​
Helen [10]

Answer and Step-by-step explanation:

Capricornus is a zodiac thing. Its name is Latin and it means "horned goat" or "goat horn" or "having horns like a goat's", it is something along those lines. It is commonly represented in the form of a sea goat.

6 0
3 years ago
HELP ASAP WILL GIVE BRAINLEST
blondinia [14]

Answer: d-9

Step-by-step explanation: d equals the savings so it says she spent four dollars and then five, so just add those and subtract it from the savings

5 0
3 years ago
Read 2 more answers
The map of a mall is overlaid with a numeric
Veseljchak [2.6K]

Answer:

\sqrt{118}<em> or 10.8627805 </em>

Step-by-step explanation:

Start by taking the difference of each value of both points

<u>Find the difference in x values </u>

78-2 = 76

<u>Find the difference in y values</u>

46-4 = 42

<u>Add the two differences </u>

76+42=118

<u>Take the square root of this value </u>

<u />\sqrt{118}<u />

3 0
4 years ago
Today there are a total of six toll-free area codes: 800, 844, 855, 866, 877, and 888. Assume that all seven digits for the rest
Ludmilka [50]

Answer:

6 \times 10^{7}

Step-by-step explanation:

Total number of toll-free area codes = 6

A complete number will be of the form:

800-abc-defg

Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.

Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.

Considering: 800-abc-defg

The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.

Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:

Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = 10^{7}

Since, there are 6 toll-free are codes in total, the total number of toll-free numbers for all 6 area codes = 6 \times 10^{7}

4 0
3 years ago
Find the sum of the sequence. 45+46+47+48+...+108
Anna11 [10]
We know, S = n/2 [ a + l ]
Here, a = 45
l = 108

Calculation of n:
a(n) = a + (n - 1)d
108 = 45 + (n - 1)1
108 - 45 = n - 1
63 + 1 = n
n = 64

Now, substitute in the expression:
S = 64/2 [ 45 + 108 ]
S = 32 [ 153 ]
S = 4896

In short, Your Answer would be 4896

Hope this helps!
7 0
4 years ago
Read 2 more answers
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