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Radda [10]
3 years ago
9

The Honor Society decided to have t-shirts made for each member. There is a screen printing fee of $15 and each t-shirt costs $4

.75. The total bill for having the t-shirts made was $143.25.
How many members are there in the Honor Society?
Mathematics
2 answers:
stealth61 [152]3 years ago
7 0
To find the answer, here's the equation:
143.25/15+4.75
= 143.25 / 19.75
which is about 7.25.
We can assume that about 8 people are in the honor society.
I might be wrong, though...
SIZIF [17.4K]3 years ago
4 0
The answer is 7 members i hope this helps 
plz make me brainlist
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3 years ago
Deijah gave Isaiah $6.25 in nickels and quarters. If 12 coins were quarters, how many coins were nickels? Which equation models
dem82 [27]
Deijah has $6.25. 

Now, this 6.25 is comprised of 0.05s and 0.25s. 
We know that there are 12 0.25s.

We now want to know how many remaining 0.05s there are.

Again, we know that the number of 0.05s he has, which is 12, multiplied by 0.05, plus the number of 0.25s he has, multiplied by 0.25, equals 6.25.

Thus, the answer is A, 0.25 x 12 + 0.05 x n = 6.25.
4 0
3 years ago
1. Which one of the following statements is true of perpendicular lines?
Dovator [93]
Only D is correct, it intersects at 90 degrees so it cant be obtuse or acute and never intersecting would be parallel lines <span />
7 0
3 years ago
Read 2 more answers
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Tomtit [17]

Apparently my answer was unclear the first time?

The flux of <em>F</em> across <em>S</em> is given by the surface integral,

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S

Parameterize <em>S</em> by the vector-valued function <em>r</em>(<em>u</em>, <em>v</em>) defined by

\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k

with 0 ≤ <em>u</em> ≤ π/2 and 0 ≤ <em>v</em> ≤ π/2. Then the surface element is

d<em>S</em> = <em>n</em> • d<em>S</em>

where <em>n</em> is the normal vector to the surface. Take it to be

\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}

The surface element reduces to

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv

so that it points toward the origin at any point on <em>S</em>.

Then the integral with respect to <em>u</em> and <em>v</em> is

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS

=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS

=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}

4 0
3 years ago
Can someone please help me with this <br><br><br> |<br> |<br> |
Ede4ka [16]
The answer could be 45 but I'm not entirely sure
7 0
3 years ago
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