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3 years ago

The question is in the picture

Mathematics

2 answers:

ladessa [460]3 years ago

8 0

Answer: 2

Step-by-step explanation: It is the only point on the Y line.

melamori03 [73]3 years ago

6 0

2! goodluck kiddo!!!!

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Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every

Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

$A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}$

For machine B:

$B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}$

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

$A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}$

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

$t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }$

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

$t = \frac{200}{8} s = 25 s$

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

4 0

3 years ago

Read 2 more answers

What is the first step in simplifying the expression

Mama L [17]

For this case we have the following expression:

$\frac {11x-2-3 (1-7x) ^ 2} {(x + 1)}$

We must indicate the first step that allows to start the simplification of the expression.

It is observed that the first step to follow is to solve the square of the binomial that is in the numerator of the expression.

$(1-7x) ^ 2$

Answer:

Option A

6 0

3 years ago

Read 2 more answers

Suppose that f : [a, b] → [a, b] is continuous. Prove that f has a fixed point. That is, prove that there exists c ∈ [a, b] such

nikklg [1K]

Answer:

Step-by-step explanation:

define the function:

$g(x) = f(x) -x$

As both $f(x)$ and x are continuous functions, $g(x)$ will also be continuous.

Now, what can we say about $g(a) = f(a) -a$ ?

we know that $a\leq f(a) \leq b$ , thus:

$a-a\leq f(a)-a \leq b-a\\0 \leq g(a) \leq b-a$

thus $g(a)$ is non-negative.

What about $g(b)$ ? Again we have:

$a\leq f(b) \leq b\\a-b \leq f(b) -b \leq 0\\a-b \leq g(b) \leq 0$

That means that $g(b)$ is not positive.

Now, we can imagine two cases, either one of $g(a)$ or $g(b)$ is equal to zero, or none of them is. If either of them is equal to zero, we have found a fixed point! In fact, any point $c$ for which $g(c)=0$ is a fixed point, because:

$g(c) = 0 \implies f(c) -c = 0 \implies f(c) = c$

Now, if $g(a) \neq 0$ and $g(b) \neq 0$ , then we have that

$g(a) >0$ and $g(b) < 0$ . And by Bolzano's theorem we can assert that there must exist a point c between a and b for which $g(c)=0$ . And as we have shown before that point would be a fixed point. This completes the proof.