Answer:
Vertical Angles
Step-by-step explanation:
Hope this helps
Answer:
4.891
its side b (opposite side of the 50 degree angle)
Step-by-step explanation:
side c = 6
angle A is 20 side a (opposite side) = 2.184
angle B is 50 side b (opposite side) = 4.891
angle C is 110 side c (opposite side) = 6
1.
get third angle
50 + 20 = 70
180 - 70 = 110
third angle C is 110
2.
get side a
sin A/a = sin C/c
a/c = sinA/sinC
a = c * sinA/sinC
a = 6 * (sin20/sin110)
get sin in degrees
a = 6 * (.342/.9397)
a = 2.184
#7:
It means to solve for y.
#8:
We can write:
l = w + 2
Because it says the length is 2 more than the width.
Compute the derivative dy/dx using the power, product, and chain rules. Given
x³ + y³ = 11xy
differentiate both sides with respect to x to get
3x² + 3y² dy/dx = 11y + 11x dy/dx
Solve for dy/dx :
(3y² - 11x) dy/dx = 11y - 3x²
dy/dx = (11y - 3x²)/(3y² - 11x)
The tangent line to the curve is horizontal when the slope dy/dx = 0; this happens when
11y - 3x² = 0
or
y = 3/11 x²
(provided that 3y² - 11x ≠ 0)
Substitute y into into the original equation:
x³ + (3/11 x²)³ = 11x (3/11 x²)
x³ + (3/11)³ x⁶ = 3x³
(3/11)³ x⁶ - 2x³ = 0
x³ ((3/11)³ x³ - 2) = 0
One (actually three) of the solutions is x = 0, which corresponds to the origin (0,0). This leaves us with
(3/11)³ x³ - 2 = 0
(3/11 x)³ - 2 = 0
(3/11 x)³ = 2
3/11 x = ³√2
x = (11•³√2)/3
Solving for y gives
y = 3/11 x²
y = 3/11 ((11•³√2)/3)²
y = (11•³√4)/3
So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).