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Dafna1 [17]
3 years ago
14

IM TAKING A TEST HELP

Mathematics
2 answers:
rodikova [14]3 years ago
6 0
Hope this helped :).
nignag [31]3 years ago
5 0
What’s the question???...
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What does mx+b stand for
S_A_V [24]

Answer:

thats the equation for slope-intercept form

Step-by-step explanation:

m is the slope and b is where the line intercepts on the y axis

4 0
2 years ago
Read 2 more answers
1. 4x– 15 = 17 - 4x+10x<br> Help?
Nadya [2.5K]

Answer:

x=-16

Step-by-step explanation:

4x– 15 = 17 - 4x+10x

4x+4x-10x = 17+15

-2x=32

-x=16

x=-16

7 0
3 years ago
Which shows the expression below in simplified form?
statuscvo [17]

Answer:

B. 9x10^4

Step-by-step explanation:

\frac{4.5 \times  {10}^{8} }{5 \times  {10}^{3} }  \\  = 0.9 \times  {10}^{8 - 3}  \\  = 0.9 \times  {10}^{5}  \\  = 9 \times  {10}^{4}

5 0
3 years ago
Draw a net for each of the following shapes:
Margarita [4]
A. You would start off by a rectangle in the middle, then you would place to squares on the bottom and top if the rectangle. After you've done that, you place two rectangles (Same size as the original) on both sides of the original rectangle. Finally you add a rectangle (Same size) to either ends of the secondary rectangles. It should look like this.


B. You would start off with a rectangle in the middle, then you would add 2 equilateral triangles to the top and bottom of the rectangle. After that, you Simply put 2 rectangles (Same size as the original) on both sides of the rectangle. It should look something like this.

C. To make a pyramid, it's actually quite simple. You would start off with a square in the middle, and then place equilateral triangles on ALL sides of the square. It should look something like this.

I hope this helped ^^

4 0
3 years ago
PLEASE HELP ME WITH THESE FOUR QUESTIONS TYSMMM!!! THANK YOU
Dima020 [189]

Answer:

107^\circ, 133^\circ, 20^\circ, \text{and}, 23^\circ

Step-by-step explanation:

9. For the lines 'm' and 'n' to be parallel the sum of interior angles should be 180 degrees that is:

x+73^\circ=180^\circ

x=107^\circ

10. For the lines  'm' and 'n' to be parallel the alternate exterior angles should be equal that is:

147^\circ=x+14^\circ

x=147^\circ-14^\circ

x=133^\circ

11. For the lines  'm' and 'n' to be parallel alternate angles should be equal that is:

180^\circ-3x=2x+20^\circ

Solving for 'x' we get:

180^\circ-20^\circ=3x+2x

5x=160^\circ

x=32^\circ

12. For the lines  'm' and 'n' to be parallel corresponding angles should be equal that is:

(7x-11)^\circ=(4x+58)^\circ

7x-4x=58^\circ+11^\circ

3x=69^\circ

x=\frac{69}{3}=23^\circ

8 0
3 years ago
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