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Damm [24]
3 years ago
13

3z-4=6z-17 how do solve

Mathematics
2 answers:
den301095 [7]3 years ago
6 0
3z - 4 = 6z - 17.               First try to take all the zs to one side of the equation
                                      preferrably to the left. And the sign of any expression
                                      changes on crossing the equality sign.

3z-6z = -17+4
-3z     =  +4-17
-3z     =   - 13.                       Divide both sides by -3.
 -3z/-3   =  -13/-3
 
z = 13/3.  

Maru [420]3 years ago
5 0
3z-4=6z-17
-3z-4=-17 (subtracted the 6z from both sides)
-3z=-13 (added the 4 to both sides)
z=\frac{-13}{-3z} (divided both sides by -3z)
z=\frac{13}{3}
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3 years ago
simply combining like teams 3a-2b-ab-(a-b+ab)-4ab+2b-a if l write tge answers as 1a- 6ab is it correct ?​
Semenov [28]

Answer:

-6 a b + b + a

Step-by-step explanation:

Simplify the following:

-(a - b + a b) - a b - 4 a b + 2 b - 2 b + 3 a - a

Hint: | Group like terms in 3 a - 2 b - a b - (a b - b + a) - 4 a b + 2 b - a.

Grouping like terms, 3 a - 2 b - a b - (a b - b + a) - 4 a b + 2 b - a = -(a b - b + a) + (-a b - 4 a b) + (3 a - a) + (2 b - 2 b):

-(a b - b + a) + (-a b - 4 a b) + (3 a - a) + (2 b - 2 b)

Hint: | Combine like terms in -a b - 4 a b.

a b (-1) + a b (-4) = -5 a b:

-(a b - b + a) + -5 a b + (3 a - a) + (2 b - 2 b)

Hint: | Combine like terms in 3 a - a.

3 a - a = 2 a:

-(a b - b + a) - 5 a b + 2 a + (2 b - 2 b)

Hint: | Look for the difference of two identical terms.

2 b - 2 b = 0:

-(a b - b + a) - 5 a b + 2 a

Hint: | Distribute -1 over a b - b + a.

-(a b - b + a) = -a b + b - a:

-a b + b - a - 5 a b + 2 a

Hint: | Group like terms in -a b - 5 a b + b + 2 a - a.

Grouping like terms, -a b - 5 a b + b + 2 a - a = (-a b - 5 a b) + b + (-a + 2 a):

(-a b - 5 a b) + b + (-a + 2 a)

Hint: | Combine like terms in -a b - 5 a b.

a b (-1) + a b (-5) = -6 a b:

-6 a b + b + (2 a - a)

Hint: | Combine like terms in 2 a - a.

2 a - a = a:

Answer: -6 a b + b + a

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3 years ago
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Answer: 0.09

Step-by-step explanation:

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