Answer:
-(33+110z)/10z
Step-by-step explanation:
(-7/2z +4)+(1/5z -15)
from BODMAS, solving the one in the bracket
First(-7/2z +4)+(1/5z -15)
Find the Lcm
[-7/2z +4] +[1/5z -15]
(7+8z)/2z +(1-75z)/5z
find the Lcm which is 10z
[5(-7+8z) + 2(1-75z)]/10z
[(-35+40z)+(2-150z)]10z
(-35+2+40z-150z)/10z
(-33-110z)/10z
-(33+110z)/10z
Answer: (y-3)^2= 52(x+7)
The focus is (-10, -7) and the directrix is x=16. The y-coordinate of the vertex should be same as the focus(k=-7). Then the x-coordinate of the vertex would be:
p + (-10)= 16 - p
2p= 16 + 10
p=26/2= 13
The x-coordinate of the vertex would be:
h= p+ (-10)
h= 13 - 10= 3
The vertex coordinate would be: (h, k)= (3, -7)
For a vertex (h, k), the formula for equation would be
(y-k)^2=4 p(x-h)
(y-3)^2= 4*13(x--7)
(y-3)^2= 52(x+7)
Answer:
a = 12, b = 2, c = 11
Step-by-step explanation:
Simplify the left side
Numerator simplifies: (x^5yz^4)(x^5yz^4)(x^5yz^4) goes to x^15y^3z^12
Take the new numerator and simplify with the denominator:
x^15y^3z^12/x^3yz goes to x^12y^2z^11
That means a = 12, b= 2, c = 11
Answer:
The ratios are both identical. (4 over 5 and 4 over 5)
Step-by-step explanation:
Th picture below represent the image you are referring.
sin x = opposite / hypotenuse
opposite side = 4
hypotenuse = 5
sin x° = 4/5
cos y° = adjacent/hypotenuse
adjacent = 4
hypotenuse = 5
cos y° = 4/5
The ratios are both identical (4 over 5 and 4 over 5)
