Question

Can someone please help me ASAP

Answer 1

$y=4-x^2\\x-y=2 \\ \\ y = 4 - {x}^{2} \\ x = 2 + y \\ \\ y = 4 - {(2 + y)}^{2} \\ {y}^{2} + 5y = 0 \\ y(y + 5) = 0 \\ y = 0 \\ y = - 5$

$x = 2 + 0 = 2$

$x = 2 + ( - 5) = -3$