Answer:
I tried P as the Principle invested: 750, i, as the interest rate per compounding period = 8.2/100 = 0.082 n, number of compounding periods = 2, and t, time is 6 (6 months before July 1 from January 1?) Because I got 1931.03 and it's wrong:
Step-by-step explanation:
Answer:
1099/11=99.9
since you can't have 99 boxes, you round to 100 boxes.
you will need 100 boxes.
The amount you will repay can be solved by:
Amount to be repaid = ( $ 1, 431 borrowed) ( $ 0.31 per day
/ $ 500 borrowed) 151 days
Amount to be repaid = $ 133.97
The annual interest rate is:
1431 + 133.97 = 1431( 1 + i)^ 151(1/360)
Solve for i
i = 0.2378 or 23.78 % per year
Answer:
1/12
Step-by-step explanation:
You have to have the same denominators to solve this problem, so you can multiply 2/3 by 4/4, giving you an equivalent fraction of 8/12. When you subtract 7/12 from 8/12, you get 1/12 because 8-7=1
Hola!
x = 7 , x = -7
Explicación:
Comienza restando 15 en cada lado:

Usted obtiene:

Ahora divide ambos lados por 2:

Usted obtiene:

Como la ecuación está al cuadrado, tendrás que hacer:

que te da: 
Entonces:
