Im sorry but this is not a quotient problem but an addition one, I can still simplyfy it for you though.
answer :
a) (0.17 ac)×(126 min/ac) = 21.42 min
b) I can mow 1/126 ac/min; you can mow 1/117 ac/min. Together, we can mow at a rate that is the sum of these:
... (1/126 + 1/117) ac/min = (117 + 126)/(126×117) = 243/14,742 ac/min
Then it will take 14,742/243 min/ac × 0.17 ac/lawn ≈ 10.31 min/lawn
For this problem, I'd use cross-multiplication.
9/12 = x/8.
When cross multiplying, multiply 12*x and 9*8. This leads to a new equation:
12x = 72.
Then you solve as an algebra problem.
*Divide 12 on both sides*
x = 6.
Answer:

Step-by-step explanation:
Raising something to a power to a power simply simply multiplies the two exponents
(n^3)^2 = n^6
(n^5)^4 = n^20
Multiplying two numbers with the same base (n) will add the exponents
n^6 x n^20 = n^26
Answer:B
Step-by-step explanation: