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4 years ago

Four polynomials are shown below:

1 answer:

8 0

The appropriate choice is
Polynomial B. -3x⁴ +5x³ +5

_____
C and D are not trinomials. (They have 4 terms, not 3.) A is 5th degree, not 4th.

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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

What are two multiplication digits that equal to 3030

xz_007 [3.2K]

So x times y=3030
x and y=unknown
find the factors (factors of 6=2 and 3)
3030=2,3,5,101 so
two multiplication is
2 times 1515
3 times 1010
5 times 606
30 times 101
202 times 15
303 times 10
505 times 6

5 0

3 years ago

Marys family had to pay 3$ for the car plus 2$ for each number of people in the car.

Gala2k [10]

Answer:

y=2x+3

Step-by-step explanation:

Y is the total amount that the family pays. 2x represents 2 dollars for every person (so, 2 multiplied by the number of people). Finally, 3 represents the initial amount that they must pay, no matter how many are in the car.

8 0

3 years ago

Read 2 more answers

Form a sequence that has two arithmetic means between 13 and 88.

hichkok12 [17]

Answer:

Correct choice is A

Step-by-step explanation:

For the numbers 13 and 88, find the difference 88-13:

since 88-13=75 and $\dfrac{75}{3}=25$ (two arithmetic means tells you there will be three intervals), two arithmetic means will be