If
represent a family of surfaces for different values of the constant
. The gradient of the function
defined as
is a vector normal to the surface
.
Given <span>the paraboloid
.
We can rewrite it as a scalar value function f as follows:
The normal to the </span><span>paraboloid at any point is given by:
Also, the normal to the given plane
is given by:
Equating the two normal vectors, we have:
</span>
Since, -1 = 2 is not possible, therefore
there exist no such point <span>
on the paraboloid such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>
.
Answer:
NOT a solution
Step-by-step explanation:
Substitute the values of x and y and see if the equation is satisfied:
3(1) -7(-1) = 3 +7 = 10 ≠ 4 . . . . . . the given point is not on the line
(1, -1) is not a solution to the equation.
_____
(-1, 1) is a solution
Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(-5,-9)...x1 = -5, and y1 = -9
(-5,13)...x2 = -5 and y2 = 13
now we sub and solve
d = sqrt (-5 - (-5)^2 + (13 - (-9)^2
d = sqrt (-5 + 5)^2 + (13 + 9)^2
d = sqrt (0^2 + 22^2)
d = sqrt (484)
d = 22 <==
make the y int -4 because it passes through (0,-4). to make perpendicular, apply same slope to new equation but change sign
Answer:
3.5 or 3 1/2 feet of the shelf
Step-by-step explanation: