Answer:
£14889.30
Step-by-step explanation:
The cost of the car = £15500.
For the first year,
depreciation = £15500 x 1%
= £155
Its worth after the first year = £15500 - £155
= £15345
For the 2nd year,
depreciation = £15345 x 1%
= £153.45
Its worth after the second year = £15345 - £153.45
= £15191.55
For the 3rd year,
depreciation = £15191.55 x 1%
= £151.9155
Its worth after the third year = £15191.55 - £151.9155
= £15039.6345
For the 4th year,
depreciation = £15039.6345 x 1%
= £150.3963
Its worth after the fourth year = £15039.6345 - £150.3963
= £14889.2382
Thus, the worth of the car in 4 years would be £14889.30
Answer:
A.)359.2, B.)2.5 uf
Step-by-step explanation:
E / I = R
208 / 1.04 = 200 ohms
2*pi*f*L = Xl
6.28*400*.143 = 359.2 ohm
1 / (2*pi*f*Xc) = c
1 /(6.28*400*159.2) = 2.5 uf
If your answer was d) 3.6 , then you are correct!
<em>Answer: h = 120 ft; w = 80 ft </em>
<em></em>
<em>A = 9600 ft^2</em>
<em />
<em>Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:</em>
<em></em>
<em>A = h*w (eq1)</em>
<em></em>
<em>The total amount of fence used is:</em>
<em></em>
<em>L = 2*h + 2*w + w (eq2) (an extra distance w beacuse of the division)</em>
<em></em>
<em>Solving for w:</em>
<em></em>
<em>w = L - 2/3*h = 480 - 2/3*h (eq3) Replacing this into the area eq:</em>
<em></em>
<em></em>
<em></em>
<em>We derive this and equal zero to find its maximum:</em>
<em></em>
<em> Solving for h:</em>
<em></em>
<em>h = 120 ft. Replacing this into eq3:</em>
<em></em>
<em>w = 80ft</em>
<em></em>
<em>Therefore the maximum area is:</em>
<em></em>
<em>A = 9600 ft^2</em>
<em />
Answer:
0,-3
Step-by-step explanation:
because its across it so it probbly dose not cam o it dose poloyn it
