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Vladimir [108]
2 years ago
15

Colin buys a car for £15500.

Mathematics
1 answer:
timama [110]2 years ago
8 0

Answer:

£14889.30

Step-by-step explanation:

The cost of the car = £15500.

For the first year,

depreciation = £15500 x 1%

                     = £155

Its worth after the first year = £15500 - £155

                             = £15345

For the 2nd year,

depreciation = £15345 x 1%

                     = £153.45

Its worth after the second year = £15345 - £153.45

                                 = £15191.55

For the 3rd year,

depreciation = £15191.55 x 1%

                      = £151.9155

Its worth after the third year = £15191.55 - £151.9155

                                            = £15039.6345

For the 4th year,

depreciation = £15039.6345 x 1%

                     = £150.3963

Its worth after the fourth year = £15039.6345 - £150.3963

                                             = £14889.2382

Thus, the worth of the car in 4 years would be £14889.30

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3 years ago
The linear function that is represented by which table has the same slope as the graph? On a coordinate plane, a line goes throu
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