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Anastasy [175]
3 years ago
15

What is the absolute value of the complex number -4-√2

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0
|a+bi| = √(a² + b²)

-4-√2 i -> take a = -4 and b = -√2

|-4-√2 i| = √[ (-4)² + (<span>-√2)² ]
               = </span><span>√[ 16 + 2<span> ]
               </span></span><span>= √[ 18 ]</span> = <span>√[ 9 * 2 ]
               = 3√2
the absolute value is 3√2</span>

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Step-by-step explanation:

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What is X in this question: x/3+x/4+1=x/2
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Step-by-step explanation:

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Sonya can walk 6 kilometers in 3 hours. If she has to walk 10 kilometers, how much time will it take her?
ELEN [110]
6 divided by 2 is 3 kilometers.
Therefore, divide 10 by 2 which will get you 5 kilometers.

Sonya can walk 10 kilometers in 5 hours.
6 0
2 years ago
Plz help<br>urgent !!!!<br>will give the brainliest !!​
Mkey [24]

Answer:

X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}

Step-by-step explanation:

The question we have at hand is, in other words,

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix} - where we have to solve for the value of X

If we have to isolate X here, then we would have to take the inverse of the following matrix ...

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix} ... so that it should be as follows ... \begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}

Therefore, we can conclude that the equation as to solve for " X " will be the following,

X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} - First find the 2 x 2 matrix inverse of the first portion,

\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1} = \frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}= \frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix} = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} ,

X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix} - Simplifying this, we should get ...

\begin{bmatrix}1&3\\ 2&4\end{bmatrix} ... which is our solution.

7 0
3 years ago
Quadrilateral KLMN has vertices of K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4) Find the length of MN
Olenka [21]

Answer:

The length of MN is \sqrt{5} units.

Step-by-step explanation:

The given Quadrilateral KLMN has vertices at K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4).

We use the distance formula to find the length of MN.

|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We plug in the values to get

|MN|=\sqrt{(-4--2)^2+(-4--5)^2}

|MN|=\sqrt{(-2)^2+(1)^2}

|MN|=\sqrt{4+1}

|MN|=\sqrt{5}

The length of MN is \sqrt{5} units.

3 0
3 years ago
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