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lesya [120]
3 years ago
8

How to turn a fraction into a division problem?

Mathematics
1 answer:
V125BC [204]3 years ago
3 0
X/y = x divided by y
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Help meh please..................
madam [21]

Answer:

The correct answer is B.  (2x and 7y)

Step-by-step explanation:

You cannot combine x to y therefore they are considered unlike terms .

3 0
3 years ago
Read 2 more answers
David bought 3 dvds and 4 books for $40 at a yard sale. Anna bought 1 dvd and 6 books for $18. How much did each dvd and book co
Ber [7]

Answer:

A book is worth $1 and a DVD is worth $12.

Step-by-step explanation:

The equations (2 unknowns and two equations, d is for a DVD and b is for a book):

For David: 3d+4b=40

For Anna: d+6b=18

Now multiply the second equation with -3 and add to the first equation:

3d+4b=40

−3d−18b=−54

Combined equation: −14b=−14 and b=1 (means that each book is worth $1).

 

Now for DVD price, use the second equation:

d=18−6 or d=12 (means that each DVD  is worth $12).

A book is worth $1 and a DVD is worth $12.

8 0
3 years ago
Of the following expressions, which is equal to 6(√10)?
Inessa [10]

Answer:

sqrt(360)

Step-by-step explanation:

sqrt(360)=sqrt(36*10)=sqrt(36)*sqrt(10)=6*sqrt(10)

8 0
3 years ago
Malika earn $40.25 for three and a half hours of overtime work on Saturday determine Malika's overtime pay rate
Roman55 [17]
Just divide 40.25 by 3.5. You get 11.5. So his pay rate is 11.5 every hour.

I hope this helps :)
8 0
3 years ago
manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
Naddik [55]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
6 0
3 years ago
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