2x-3y = 8
Add 3y on both sides
2x = 8 + 3y
Subtract 8 on both sides
3y = 2x - 8
Divide 3 on both sides
Add 3y on both sides
2x = 8 + 3y
Subtract 8 on both sides
3y = 2x - 8
Divide 3 on both sides
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2 answers:
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Answer:
C
Step-by-step explanation:
Since the triangle is right with hypotenuse QR
Use Pythagoras' identity to solve for QR
The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
QR² = 8² + (8 )²
= 64 + 192
= 256 ( take the square root of both sides )
QR = = 16