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3 years ago

Y=(x-k)^3 and y=x^3 will these two graphs ever concide

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

5 0

Answer: this is the awnser

Step-by-step explanation:

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How many times does 22 go into 160

lara [203]

The answer is 7 remainder 2.

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3 years ago

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Dan learned the mass of an electron is about 9.1×10⁻³¹ while the mass of a proton is about 1.7×10⁻²⁷. He thinks electrons have a

Lyrx [107]

Answer:so I will try.

Step-by-step explanation:but it might take a will

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3 years ago

(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +

jekas [21]

Answer:

1. The slope of the line is $m=\frac{-2b+3}{2a}$ .

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

$m=\frac{y_2-y_1}{x_2-x_1}$

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

$m=\frac{-b-(b-3)}{a+3-(-a+3)}$

$m=\frac{-b-b+3}{a+3+a-3)}$

$m=\frac{-2b+3}{2a}$

The slope of the line is $m=\frac{-2b+3}{2a}$ .

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

$m_1=\frac{5-1}{6-a}=\frac{4}{6-a}$

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

$m_2=\frac{1-7}{a+2-2}=\frac{-6}{a}$

The slopes of two parallel lines are same.

$m_1=m_2$

$\frac{4}{6-a}=\frac{-6}{a}$

On cross multiplication we get

$4a=-6(6-a)$

$4a=-36+6a$

$4a-6a=-36$

$-2a=-36$

Divide both sides by -2.

$a=18$

Therefore the value of a is 18.

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3 years ago

Prove that u(n) is a group under the operation of multiplication modulo n.

katrin2010 [14]

Answer:

The answer is the proof so it is long.

The question doesn't define u(n), but it's not hard to guess.

Group G with operation ∘

For all a and b and c in G:

1) identity: e ∈ G, e∘a = a∘e = a,

2) inverse: a' ∈ G, a∘a' = a'∘a = e,

3) closed: a∘b ∈ G,

4) associative: (a∘b)∘c = a∘(b∘c),

5) (optional) commutative: a∘b = b∘a.

Define group u(n) for n prime is the set of integers 0 < i < n with operation multiplication modulo n.

If n isn't prime, we exclude from the group all integers which share factors with n.

Identity: e = 1. Clearly 1∘a = a∘1 = a. (a is already < n).

Closed: u(n) is closed for n prime. We must show that for all a, b ∈ u(n), the integer product ab is not divisible by n, so that ab ≢ 0 (mod n). Since n is prime, ab ≠ n. Since a < n, b < n, no factors of ab can equal prime n. (If n isn't prime, we already excluded from u(n) all integers sharing factors with n).

Inverse: for all a ∈ u(n), there is a' ∈ u(n) with a∘a' = 1. To find a', we apply Euclid's algorithm and write 1 as a linear combination of n and a. The coefficient of a is a' < n.

Associative and Commutative:

(a∘b)∘c = a∘(b∘c) because (ab)c = a(bc)

a∘b = b∘a because ab = ba.

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3 years ago

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Find the slope of the line that goes through the given points. (-10, -3) and (-7, -9)

Hatshy [7]

Answer:

-2

Step-by-step explanation:

rise over run or, y2-y1/x2-x1

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3 years ago