5^5-9(200/4)-(10*90)/5-4^4(5)+156-256
= 3125-9( 200/4)-(10*90)/5-(4^4)(5)+156-256
= 3125-(9)(50)- (10*90)/5-(4^4)(5)+156-256
= 3125-450- (10*90)/5-(4^4)(5)+156-256
= 2675-(10*90)/5-(4^4)(5)+156-256
= 2675 - 900/5 - (4^4)(5)+156-256
= 2675 - 180 - (4^4)(5)+156-256
= 2495 - (4^4)(5)+156-256
= 2495 - 1280 + 156 -256
= 1215 + 156 - 256
= 1371 - 256
= 1115
I hope that's help , please if you have question(s) just let me know !
Answer:
The answer is Negative 4, -4
Step-by-step explanation:
Answer:
She can type 225 words in 10 minutes
Step-by-step explanation:
We can find the rate by dividing the number of words by the time
90 words/ 4 minutes
22.5 words per minute
Now to find the number of words in 10 minutes, multiply the rate times the time
22.5 * 10 = 225
She can type 225 words in 10 minutes
Let, Jason = J and M = Megan
M = J(1 + 1/4)
So putting 6 where J is and solving:
<em>M = 6(1 + 1/4)
</em><em>M= 7.5</em>
When Jason runs 6 miles Megan runs 7.5
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Answer:
34.87% probability that all 5 have a wireless device
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
81% of students own a wireless device.
This means that
If 5 students are selected at random, what is the probability that all 5 have a wireless device?
This is P(X = 5) when n = 5. So
34.87% probability that all 5 have a wireless device