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Colt1911 [192]
3 years ago
14

Why are there limitations on the values of the base of an exponential function?

Mathematics
1 answer:
anygoal [31]3 years ago
7 0

Exponential functions look somewhat similar to functions you have seen before, in that they involve exponents, but there is a big difference, in that the variable is now the power, rather than the base. Previously, you have dealt with such functions as<span>f(x) = x2</span><span>, where the variable </span>x<span> was the base and the number </span>2<span> was the power. In the case of exponentials, however, you will be dealing with functions such as </span><span>g(x) = 2</span>x, where the base is the fixed number, and the power is the variable.

Let's look more closely at the function <span>g(x) = 2</span>x<span>. To evaluate this function, we operate as usual, picking values of </span>x<span>, plugging them in, and simplifying for the answers. But to evaluate </span>2x<span>, we need to remember how exponents work. In particular, we need to remember that </span>negative exponents<span> mean "put the base on the other side of the fraction line.   </span>

<span>
</span>

<span>hope this help plz mark brainliest</span>

<span>
</span>

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Luke bought a jacket that was 30% off the cost. He paid sales tax of 6% after the discount had been applied. If the jacket had a
nasty-shy [4]

Answer: the actual amount that Luke paid including tax is $55.65

Step-by-step explanation:

The initial price of the jacket is $75.

Luke bought a jacket that was 30% off the cost. This means that the amount of discount on the Jacket is

30/100 × 75 = 0.3 × 75 = $22.5

The price of the jacket after the discount had been applied is

75 - 22.5 = $52.5

He paid sales tax of 6% after the discount had been applied. This means that the amount of sales tax that he paid on the jacket is

6/100 × 52.5 = 0.06 × 52.5 = 3.15

Therefore, the actual amount that Luke paid including tax is

52.5 + 3.15 = $55.65

5 0
4 years ago
Write an equation to represent the following statement.
svetoff [14.1K]

Answer/explanation:

60=5k 

Is the equation because the word is means equals, so we add an equal sign after the 60. Five times greater simply means multiply so we multiply 5 and k.

To solve the equation, you would need to divide both sides by 5 to isolate the variable

60/5=5k/5

12=k 

7 0
3 years ago
8th grade math probability
kari74 [83]
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3 0
3 years ago
Select all of the following tables which represent y as a function of x.x 5 10 11y 3 9 15x 5 10 11y 3 9 9x 5 10 10y 3 9 15
11Alexandr11 [23.1K]

Answer:

Table 1 and 2 represent a function

Step-by-step explanation:

Given

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

<em>Table 2</em>

x 5 10 11

y 3 9 9

<em>Table 3</em>

x 5 10 10

y 3 9 15

Required

Determine which of the tables represent that y is a function of x

For a relation to be a function; the x values must be unique.

In other words, each x value must not be repeated;

Having said that;

Analyzing Table 1

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

Note that the x rows are unique as no value were repeated;

Hence, Table 1 is a function

<em>Table 2</em>

x 5 10 11

y 3 9 9

Note that the x rows are unique as no value were repeated;

Hence, Table 2 is a function

<em>Table 3</em>

x 5 10 10

y 3 9 15

Note that the x rows are not unique because 10 was repeated twice;

Hence, Table 3 is not a function

7 0
3 years ago
Michaels buys three over a pound of cheese he puts the same amount of cheese and three sandwiches how many cheese how much chees
Tasya [4]

Question is not proper,Proper question is given below;

Nicholas buys 3/8 pound of cheese he put the same amount of cheese and three sandwiches how much cheese does Nicholas put on each sandwich

Answer:

Nichole can put \frac{1}{8} \ pounds of cheese on each of his sandwich.

Step-by-step explanation:

Total Amount of cheese he has = \frac{3}{8} \ pound

Number of cheese sandwiches = 3

We need to find Amount of cheese does Nicole put on each of his sandwich.

Solution:

Amount of cheese on each sandwich can be calculated by dividing Total Amount of cheese he has with Number of cheese sandwiches.

framing in equation form we get;

Amount of cheese on each sandwich = \frac{\frac{3}{8}}{3}} = \frac{1}{8} \ pounds

Hence Nichole can put \frac{1}{8} \ pounds of cheese on each of his sandwich.

7 0
3 years ago
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