Press and hold down the "Fn" button while pressing the "Home Prt Sc" button above the numeric keypad to capture the entire screen. Make a screenshot of the active window only by holding down the "Fn" and Alt" keys while pressing "Home Prt Sc." 2. Press the "Start" button, and type "Paint" into the search box.
Answer:
I want to answer the 1st question. It asks, “Will we treat people unfairly for crimes they haven’t committed?” Well, of course, that’s a 100% chance. But, some people forget that people treat people unfairly for crimes they haven’t committed. Some people stay in jail for up to 35 years and are then released because they are innocent. Yes, computers will make mistakes, but the probability is much, much smaller than a human.
Explanation:
B, C, and D are the correct answers.
Answer:
hi earlier u told me to answer ur question but i couldn't respond in the comments cos it said something went wrong
Explanation:
do i answer this question seriously or is this answer good?? srry im kinda dûmb T-T
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}