Question

8x^3 -10x^2 +3x=0 please solve for x

Answer 1

$\bf 8x^3-10x^2+3x=0\implies x(8x^2-10x+3)=0 \\\\\\ x(2x-1)(4x-3)=0\implies \begin{cases} x=0\implies &x=0\\\\ 2x-1=0\implies 2x=1\implies &x=\frac{1}{2}\\\\ 4x-3=0\implies 4x=3\implies &x=\frac{3}{4} \end{cases}$

Answer 2

So x would equal to x=0, 3/4, 1/2