Answer:
Two negatives together get a positive
Step-by-step explanation:
-9-(-4)
-(-4)
+4
Step-by-step explanation:
Annie = x
Brianna = y
Carly = z
Now,
x + y + z = 105 ...(1)
Carly has sold ten more than three times Brianna's sales.
z = 10 + 3y ...(2)
Brianna sold five more than Annie.
y = 5 + x ...(3)
Now,
z = 10 + 3y
z = 10 + 3(5 + x)
z = 10 + 15 + 3x
z = 25 + 3x
Now,
x + y + z = 105
x + (5 + x) + 25 + 3x = 105
5x + 30 = 105
5x = 105 - 30
5x = 75
5x/5 = 75/5
x = 15
So,
y = 5 + x
y = 5 + 15
y = 20
Now,
z = 25 + 3x
z = 25 + 3(15)
z = 25 + 45
z = 70
Thus,
Annie Sold 15 boxes
Brianna Sold 20 boxes
Carly Sold 70 boxes
<h3>
Answer: 680 different combinations</h3>
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Explanation:
If order mattered, then we'd have 17*16*15 = 4080 different permutations. Notice how I started with 17 and counted down 1 at a a time until I had 3 slots to fill. We count down by 1 because each time we pick someone, we can't pick them again.
So we have 4080 different ways to pick 3 people if order mattered. But again order doesn't matter. All that counts is the group itself rather than the individual or how they rank. There are 3*2*1 = 6 ways to order any group of three people, which means there are 4080/6 = 680 different combinations possible.
An alternative is to use the nCr formula with n = 17 and r = 3. That formula is
where the exclamation marks indicate factorials
(a) Using the table, give the values fo rthe inverse
1) original table of values:
x 1 2 3 4 5
f(x) 0 1 1 5 3
2) The inverse of the function is obtained by exchanging x and f(x), this is:
( x, f(x) ) → ( f(x), x)
3) So, the table of values of the inverse of the given function is:
x 0 1 1 5 3
f⁻¹ (x) 0 1 2 3 4
(b) Is the inverse a function?
No, the inverse is not a function, since the table of the inverse shows that the x -value 1 has two different images.
This ambigüity is opposite to the definition of a function, which requires that any input value has only one output. For that reason, the inverse is not a function. You cannot tell whether the image of 1 is 1 or 2, because both are images of the same value.
