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3 years ago

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Mathematics

1 answer:

leva [86]3 years ago

4 0

He withdrew 20$, it says he starts with 45 but the equation says he has 25

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areas of four triangles are 40 cm^2, 90 cm^2, 202.5 cm^2 and 455.6 cm^2 are continue in sequence. the enlargement factor is 1.5,

maw [93]

Answer:

9th Triangle

Step-by-step explanation:

Given the area of four triangles: $40 cm^2, 90 cm^2, 202.5 cm^2 \:and\: 455.6 cm^2$

If the Scale factor is 1.5.

This is a geometric sequence and the common ratio is 1.5 X 1.5.

Therefore, the area of any n triangle can be determined using the function:

$A(n)=40\cdot1.5^{2(n-1)}$

We want to determine which triangle has an area greater than $15000cm^2$ .

When A(n)=15000

$40\cdot1.5^{2(n-1)}>15000\\1.5^{2(n-1)}>\frac{15000}{40} \\1.5^{2(n-1)}>375\\\text{Change to Logarithm form}\\2(n-1)>Log_{1.5}375\\\text{Applying logarithm change of base to base 10 law}\\2(n-1)>\frac{Log 375}{Log 1.5} \\2n-2>14.62\\2n>14.62+2=16.62\\n>8.31$

Therefore, the 9th triangle has an area greater than $15000cm^2$ .

5 0

3 years ago

A machine in a factor makes 2o gidgets every 1/4 hour. How many gidgets are made every hour ?

Dahasolnce [82]

Answer:

lol

Step-by-step explanation:

lollololol

llllllllllllllllllllllllooooooooooooooooooooooooooooooooooooooooollllllllllllllllllllll

6 0

3 years ago

Write in standard form a)0.00000678 b)3170000

otez555 [7]

Standard Form:

a) 0.00000678

b) 3170000

Scientific Notation:

a) 6 × $10^{4}$

b) 6.78 × $10^{-6}$

Is this what you meant?

8 0

3 years ago

Solve the equation for x.<br> – 1/2x – 3 = 4

Nana76 [90]

Answer:

x = -4

Step-by-step explanation:

Multiply both sides by 2. Move constant to the right-hand side and change the sign. Add the numbers. And change the signs on both sides of the equation.

5 0

3 years ago

Read 2 more answers

In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were consi

valentina_108 [34]

Answer:

The answer is "0.4329 ".

Step-by-step explanation:

P( three in favor of FA)

Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges

$=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2 \times 1\times 3!}\times \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!}}{\frac{11 \times10 \times 9 \times 8 \times 7 \times 6! }{5 \times 4 \times 3 \times 2 \times 1 \times 6!}}\\\\$

$=\frac{ (5 \times 4) \times(5 \times 2)}{(11 \times 3 \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329$

6 0

3 years ago