Answer:
Number of marbles with Williams at the starting = 192
Step-by-step explanation:
Let total number of marbles with Williams = m
He lost marbles = 25% of the total number
= 
= 
Remaining marbles with Williams = m - 
= 
He gave marbles to his brother =
th of the remaining marbles
= 
= 
Remaining marbles after giving marbles to his brother = 120
Therefore, 


m = 
m = 192
Number of marbles with Williams at the starting = 192
The given equation with t -1 is:
(t – 1)^3 + 6 (t – 1)^2 + 12 (t – 1) + 8
Expand each term before combining for easier visualization:
(t – 1)^3 = t^3 – 3 t^2 + 3t – 1
6 (t – 1)^2 = 6 t^2 – 12 t + 6
12 (t – 1) = 12 t - 12
Then substitute and combine:
-> t^3 – 3 t^2 + 3t – 1 + 6 t^2 – 12 t + 6 + 12 t – 12 + 8
t^3 + 3 t^2 + 3 t + 1 (ANSWER)
32*1.2=38.4 (.2 is the 20%, and the 1 adds the percent to the original cost making it a mark up)