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ki77a [65]
3 years ago
13

Reduce To Simplest Form.-1/4 - (-3/5) =​

Mathematics
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

Step-by-step explanation:

-1/4 - (-3/5) =

-1/4 + 3/5 =

-5/20 + 12/20 =

7/20 <==

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Analyze the data represented in the table and select the appropriate model
Inessa05 [86]

Answer: Option B, a linear relation.

Step-by-step explanation:

Let's analyze the points in the data:

the first 3 pairs are: (0,14.70) (10,19.03) and (20, 23.36)

We can see the differences between consecutive points and see if the relation is linear:

(10,19.03) -  (0,14.70) = ( 10 - 0, 19.03 - 14.70) = (10, 4.33) now we need to see the quotient: 4.33/10 = 0.433

(20, 23.36) - (10,19.03)  = (20 - 10, 23.36 - 19.03) = (10, 4.33), and the quotient is the same as before.

This means that the relation is a linear relation, where the slope os 0.433 and the x-intercept is 14.70, so the equation can be written as:

y(x) = 0.433*x + 14.70

3 0
3 years ago
There are 110 sixth-grade students in a Florida middle school. 40% of the students enjoy playing video games on the weekends. Us
andreyandreev [35.5K]
40/100 - (I may be wrong)

Explanation: 40% of 110 is 44 so we make this a fraction 44/110 and then simplify to get 2/5 and after that we know that 2/5 is also 40/100, meaning 40 out of 100 students like video games.
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4 ME FISHY BROTHERs :)
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542.6

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State the postulate or theorem that proves that x is parallel to y
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Converse of the alternate interior angles theorem states the postulate or theorem that proves that x is parallel to y.
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3 years ago
What changes would you make in your description of point, line, and plane?
weeeeeb [17]

Answer:

Here's a quick sketch of how to calculate the distance from a point P=(x1,y1,z1)

P

=

(

x

1

,

y

1

,

z

1

)

to a plane determined by normal vector N=(A,B,C)

N

=

(

A

,

B

,

C

)

and point Q=(x0,y0,z0)

Q

=

(

x

0

,

y

0

,

z

0

)

. The equation for the plane determined by N

N

and Q

Q

is A(x−x0)+B(y−y0)+C(z−z0)=0

A

(

x

−

x

0

)

+

B

(

y

−

y

0

)

+

C

(

z

−

z

0

)

=

0

, which we could write as Ax+By+Cz+D=0

A

x

+

B

y

+

C

z

+

D

=

0

, where D=−Ax0−By0−Cz0

D

=

−

A

x

0

−

B

y

0

−

C

z

0

.

This applet demonstrates the setup of the problem and the method we will use to derive a formula for the distance from the plane to the point P

P

.

Step-by-step explanation:

5 0
3 years ago
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