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Marizza181 [45]
2 years ago
9

Can someone simplfy to me why we use different formula in some equations for sin cos tan? Like in some instances we swap variabl

es and in others we just divide and stuff and I don't understand why we do that ​
Mathematics
1 answer:
Tom [10]2 years ago
8 0
It does get confusing but there are ways to try & differentiate what is divided & what multiplied or added & subtracted when using variables wording plays a big part in what needs done. Depending what the equation is asking for. Pay close attention to the wording in each one
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Find the missing length using the pathagreham theorem. Show all steps​
Marat540 [252]

Answer:

7

Step-by-step explanation:

625 - 576 = 49

square root of 49 = 7

5 0
3 years ago
is perpendicular to and passes through point C(5, 12). If the coordinates of A and B are (-10, -3) and (7, 14), respectively, th
goblinko [34]
(5, 12) e (-10, -3)
x.......y...1
5.....12..1
-10..-3..1

12x -10y -15 + 120 -5y + 3x = 0
12x + 3x - 10y - 5y - 15 + 120 = 0
15x - 15y + 105 = 0 :(5)
3x - 5y + 21 = 0
m = -a/b
m = -3/-5
m(5) = 3/5

y-yo = m(x-xo)
y-14 = 3/5*(x-7)
y-14 = 3x/5 - 7/5
3x/5 - y + 14 - 7/5 = 0
3x/5 - 5y/5 + 70/5 - 7/5 = 0
3x - 5y + 70 - 7 =0
3x - 5y + 63 = 0
m(s) = -3/-5 = 3/5

m(r) = m(s) --> são paralelas
7 0
3 years ago
Read 2 more answers
In a group of 60 students, 18 students take Algebra I, 20 students take Algebra II, and 10 students take both subjects. How many
andreyandreev [35.5K]
Out of the total 60 students 18 take Algebra 1 and 20 take Algebra II. 10 take both. So out of the 18 taking algebra 10 are taking Algebra II. If we don't count that 10 because they are already counted in Algebra II count.  So 28 students are taking either course. Therefore 60-28 = 32 students who are not taking either of these courses
3 0
3 years ago
Read 2 more answers
Find the lengths of the missing sides in the triangle. Write your answers as integers or as decimals rounded to the nearest tent
nalin [4]

Answer:

The last one (x=11.3, y=8).

Step-by-step explanation:

1) There are three trigonometric ratios for right-angled triangles.

sin()=\frac{opposite}{hypotenuse}\\cos()=\frac{adjacent}{hypotenuse}\\tan()=\frac{opposite}{adjacent}

In a right triangle, the hypotenuse, h, is the side opposite the right angle. Relative to the acute angle θ, check the attachment, the legs are called the opposite side, o, and the adjacent side a.

2) In this case, we are given a length and an angle to find x and y.

Let's find x first. To find x we need to use sin()=\frac{opposite}{hypotenuse}.

sin(45)=\frac{8}{x}\\sin(45)x=8\\x=\frac{8}{sin(45)} \\x=11.31

Find y.

Notice that, we can use the Pythagorean Theorem (c^2=a^2+b^2) to find y.

c^2=a^2+b^2

11.31^2=8^2+b^2\\11.31^2 - 8^2 = b^2\\63.9161 = b^2\\\sqrt{63.9161} = b\\b = 7.99

3) Round them off to the nearest tenth.

x=11.31\\x=11.3

y=7.99\\y=8

Therefore, the correct choice is the last one (x=11.3, y=8).

4 0
2 years ago
The elves are loading all of the toys from Santa's workshop to the sleighs. They filled 2 small sleighs and 9 big sleighs with 2
Semmy [17]

Answer:

2*9=18 14*13=182 18+182=200

Step-by-step explanation:

well you multiply 2 times 9 and you get 18 and then you multiply 14 times 13 and you get 182 and then you 18+182 and that will give you 382.

5 0
3 years ago
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