The inequality that represents the given graph is y < x/5 -2 OR 5y < x - 10
<h3>Graph of Inequality</h3>
From the question, we are to determine the inequality that represents the graph
First, we will assume the inequality is a straight line and we will determine the equation of the line
From the graph, we have two points on the line
(0, -2) and (5, -1)
Using the formula for the equation of a line with two given point
(y - y₁)/(x -x₁) = (y₂ - y₁)/ (x₂ - x₁)
x₁ = 0
y₁ = -2
x₂ = 5
y₂ = -1
Thus,
(y - -2)/(x - 0) = (-1 - -2)/ (5 - 0)
(y +2)/(x - 0) = (-1 + 2)/ (5 - 0)
(y +2)/(x ) = 1/ 5
5(y + 2) =1(x)
5y + 10 = x
5y = x - 10
y = 1/5(x) - 2
y = x/5 - 2
Now,
Since the solution is below the line and the line is dotted
The inequality becomes
y < x/5 -2
OR
5y < x - 10
Hence, the inequality that represents the given graph is y < x/5 -2 OR 5y < x - 10
Learn more on Graph of Inequality here: brainly.com/question/17106134
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Use pythagoras
d = √(Δx² + Δy²)
d = √(12-2)² + (9-4)²
d = √(10² + 5²)
d = √(100 + 25)
d = √125
d = 5√5
d = 5 × 2.236
d = 11.18
The nearest tenth is 11.2, so the distance is near to 11.2
Answer:
PEMDAS, do multiplication first then, adddition, then subtraction
Step-by-step explanation:
Answer:
The equation that represents the motion of the string is given by:
.....[1] where t represents the time in second.
Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.
Substitute the given values in [1] we get;
or
(a)
The trigonometric function that models the motion of the string is given by:

(b)
Determine the amount of time t that it takes the string to be damped so that 
Using graphing calculator for the equation
let x = t (time in sec)
Graph as shown below in the attachment:
we get:
the amount of time t that it takes the string to be damped so that
is, 0.5 sec
Well to find the missing side you're going to need the other two. Take the one side and multiply by itself. Take the other one and multiply by itself. Add those two products. Then root it. Basically find something that multiplys by itself to get that product