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AURORKA [14]
3 years ago
8

What is 40+30+20+30+10

Mathematics
2 answers:
Elena-2011 [213]3 years ago
7 0

40+30=70

20+30=50

70+50+10=130

Hope this helps!

blsea [12.9K]3 years ago
7 0
 the answer is 130 because 40 + 30 = 70 + 20 = 90 +10 = 100 + 30 = 130

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Mark spent 1 hour 17 minutes less than Sheila reading last week. Sheila spent 55 minutes less than Pete. Pete spent 3 hours read
Irina-Kira [14]

Answer:

48 minutes

Step-by-step explanation:

Pete: 3 hours = 2 hours 60 minutes

Sheila: 2 hours 60 minutes - 55 minutes = 2 hours 5 minutes = 1 hour 65 minutes

Mark: 1 hour 65 minutes - 1 hour 17 minutes = 48 minutes

7 0
2 years ago
At a movie theatre adult tickets cost $10 and child ticjets cost $6. Which equation can be used to find s, the number of dollars
timurjin [86]

Answer:

s = 10k + 30

Step-by-step explanation:

Cost of Adults ticket = $10 per adult

Cost of Ticket = $6 per child

Number of adults = k

Number of Children = 5

s = Total cost

Total cost = (Cost per adult * number of adults) + (Cost per child * Number of children)

s = ($10 * k) + ($6 * 5)

s = $10k + $30

s = 10k + 30

4 0
2 years ago
Suppose a city with population 600,000 has been growing at a rate of 3​% per year. If this rate​ continues, find the population
andrezito [222]

Answer:

The answer should be around 1,149663 (Rounded off to the nearest whole number. Also if a population has a remainer you usually add it as 1. This is because these are people)

Step-by-step explanation:

First step involves listing the formulas being used:

600,000= population, 0.03= growth rate 22years= period

Therefore, we take the 600,000 and multiply by 1+0.03 ^22(to the power of 22 or period)

So, 600,000(1+0.03)^22

=1,149662.045 /1,149663

Hope this helps!

6 0
2 years ago
I need help solving this problem: 5x+8+3x=8+7x-6
Alex787 [66]

Hope this will help u....

5 0
3 years ago
The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (-1,8). The ball reache
ddd [48]

Answer:

Let's suppose that the hole is at y = 0m, where x is the time variable.

we know that:

The vertex is (-1s, 8m).

(i suppose x in seconds and y in meters)

At x = 1s, the ball reaches the hole, so we also have the point:

(1s, 0m).

Remember that the vertex of a quadratic equation y = a*x^2 + b*x + c is at:

x = -b/2a,

then we have:

-1 = -b/2a.

Then we have tree equations:

8m = a*(-1s)^2 + b*-1s + c

0m = a*(1s)^2 + b*1s + c

-1s = -b/2a.

First we should isolate one variable in the third equation, and then replace it in one of the other two:

1s*2a = b.

So we can replace b in the first two equations bi 1s*2a.

8m = a*1s^2 - 1s*2a*1s + c

0m = a*1s^2 + 1s*2a*1s + c

We can simplify both equations and get:

8m = a*( 1s^2 - 2s^2) + c = -a*1s^2 + c.

0m = a*(1s^2 + 2s^2) + c = a*3s^2 + c.

Easily we can isolate c in the second equation and then replace it into the first equation:

c = -a*3s^2

The first equation becomes:

8m = -a*1s^2 - a*3s^2 = -a*4s^2

a = 8m/-4s^2 = -2m/s^2.

Now with a, we can find the values of c and b.

c = -a*3s^2 = -(-2m/s^2)*3s^2 = 6m.

b = 1s*2a = 1s*(-2m/s^2) = -2m/s.

Then the equation is:

y = (-2m/s^2)*t^2 + (-2m/s)*t + 6m

5 0
3 years ago
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