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GuDViN [60]
2 years ago
7

Use the graph shown to fill in the blank. When x = -3, then y = ?

Mathematics
1 answer:
Anni [7]2 years ago
8 0

Answer:

-6

Step-by-step explanation:

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Can someone please help me figure out this problem. just figure out what 1,2, and 3
Aleksandr-060686 [28]
1 is 39. J don’t know about 2 and 3 though:(
4 0
3 years ago
which equations are equivalent to 3/4+m=-7/4 check all that apply m=10/4 m=-10/4 m=-5/2 11/4+m=-1/4 -5/4+m=-15/4 m+2=-0.5 Help f
Alecsey [184]

Answer:

The correct choices are; B,C,E, and F.

Step-by-step explanation:

The given equation is;

\frac{3}{4}+m=-\frac{7}{4}

We solve for m to obtain:

m=-\frac{7}{4}-\frac{3}{4}=-2.5

We also solve the remaining equations to see which ones give the same result.

A: m=\frac{10}{4} =2.5

B:m=-\frac{10}{4} =-2.5

C:m=-\frac{5}{2} =-2.5

D: \frac{11}{4}+m=-\frac{1}{4}

m=-\frac{1}{4}-\frac{11}{4}=-3

E: -\frac{5}{4}+m=-\frac{15}{4}

m=-\frac{15}{4}+\frac{5}{4}=-2.5

F: m+2=-0.5

m=-0.5-2=-2.5

The equivalent equations are; B,C,E, and F.

3 0
3 years ago
Read 2 more answers
Write the trigonometric expression sin(sin−1u−tan−1v) as an algebraic expression in u and v. Assume that the variables u and v r
igomit [66]

Answer:

[u – v√(1 – u²)]/√(1 + v²)

Step-by-step explanation:

Let sin^-1(u) = A, therefore sinA = u.

We know that sin(theta) = opposite/hypothenuse

Therefore, sinA = u/1 and u is the opposite side to angle A while 1 is the hypotenuse. Draw an acute triangle placing u opposite to angle A and 1 as the hypotenuse. By Pythagoras theorem the adjacent would be √(1 – u²).

By doing this, it means cosA = adjacent/hypotenuse = √(1 – u²)/1 = √(1 – u²)

Also, let tan^-1(v) = B, therefore tanB = v.

We know that tan(theta) = opposite/adjacent

Therefore, tanB = v/1 and v is the opposite side to angle B while 1 is the adjacent. Draw an acute triangle placing v opposite to angle B and 1 as the adjacent. By Pythagoras theorem the hypothenuse would be √(1 + v²).

Therefore, sinB = opposite/hypotenuse = v/√(1 + v²) and cosB = adjacent/hypotenuse = 1/√(1 + v²)

Now,

sin[sin^–1(u) – tan^–1(v)] =

sin(A – B) =

sinAcosB – sinBcosA =

u[1/√(1 + v²)] – [v/√(1 + v²)][√(1 – u²)] =

[u/√(1 + v²)] – [v√(1 – u²)/√1 + v²)] =

[u – v√(1 – u²)]/√(1 + v²).

8 0
2 years ago
Please help me I need a good grade I really need this or ,y mom will spank me please help me ¡!!!
AURORKA [14]

Answer:

A D and E

Step-by-step explanation:

3 0
3 years ago
Leila puts an integer into the "In" box of each machine.
kykrilka [37]

The machines represent equivalent expressions.

The output produced by both machines is 372

The equation represented on machine A is:

\mathbf{y = 2(5x + 3) - 24}

The equation represented on machine B is:

\mathbf{y = 4(2(x + 11) - 7)}

Where: x and y represent the inputs and the outputs, respectively

When the outputs are the same, it means:

\mathbf{y = y}

So, we have:

\mathbf{2(5x + 3) - 24 = 4(2(x + 11) - 7)}

Open brackets

\mathbf{10x + 6 - 24 = 8x + 88 - 28}

\mathbf{10x - 18 = 8x + 60}

Collect like terms

\mathbf{10x - 8x = 18 + 60}

\mathbf{2x = 78 }

Divide both sides by 2

\mathbf{x = 39 }

Substitute 39 for x in \mathbf{y = 2(5x + 3) - 24}

\mathbf{y = 2 \times (5 \times 39 + 3) - 24}

\mathbf{y = 372}

Hence, the output produced by both machines is 372

Read more about equivalent expressions at:

brainly.com/question/15715866

4 0
2 years ago
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