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3 years ago

How are the hundreds place and the hundred thousands place alike and different?

1 answer:

5 0

One is in the hundred thouseths which should be all the way in front of the
number, and one is the 2nd 3digits for example:   365, 867
                                                                                Δ      Δ
                                                                       hundred   hundreds
                                                                      thousand

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The product of three consecutive integers is 3360. What is the sum of the three integers?

Tom [10]

Step-by-step explanation:

let the integer be x .

three consecutive integers : x, x+1, x+2.

according to the problem,.

Let the first of the 3 consecutive numbers be X.

Therefore the second number is (X + 1)

The third number is therefore (X + 2)

The product of the 3 consecutive numbers is:

( X )( X + 1 )( X + 2 ) = 3360 Equation( 1 )

Expanding Equation ( 1 ) gives

X³ + 3X² + 2X - 3360 = 0 Equation (2)

Solve Equation (2 ) which gives the following values for X

X1 = 14

X2 = - 8.5 + i (12.951834)

X3 = - 8.5 - i (12.951834).

the numbers are 14,15,16.

sum is 14+15+16 = 45.

hope this helps you.

5 0

3 years ago

How to solve the second equation

ivann1987 [24]

$\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
y = &{{ -0.02}}x^2&{{ +1}}x&{{ +6}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{1^2}{2(-0.02)}~~,~~6-\cfrac{1^2}{4(-0.02)} \right)
\\\\\\
(\stackrel{\textit{how far ahead it went}}{25}~,~\stackrel{\textit{how high it went}}{18\frac{1}{2}})$

$\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
y = &{{ -0.01}}x^2&{{ +0.7}}x&{{ +6}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{0.7^2}{2(-0.01)}~~,~~6-\cfrac{0.7^2}{4(-0.01)} \right)
\\\\\\
(\stackrel{\textit{how far ahead it went}}{24\frac{1}{2}}~,~\stackrel{\textit{how high it went}}{18\frac{1}{2}})$

4 0

4 years ago

Question Number 12, i need help!! It’s geometry.

Anika [276]

X = 13

( x + 4) / 51 = (2x - 7) / 57
585 = 45x
585/45 = 45x/45
x = 13

6 0

3 years ago

Find x<br> A. 22√2<br> B. 22<br> C. 11√3/3<br> D. 11√3

mel-nik [20]

Answer

$22\sqrt{2}$

Step-by-step explanation:

First we gave a name to the side that is common for both triangles, can be Y for example.

Using trigonometric functions we can make a relationship between the two angles that we have and the magnitud of the side.

$sin(45)=\frac{11}{Y} \\$ , Because sin(x)= op/hip

$cos(60)=\frac{Y}{x}$ , Because con(x)=ad/hip

Having this equations, we can solve the system and find x

$Y=\frac{11}{sin(45)} \\Y=cos(60)*x$

we equal Y and solve

$\frac{11}{sin(45)}=cos(60)*x\\ x=\frac{11}{sin(45)*cos(60)} \\x=\frac{11}{\frac{\sqrt{2} }{2} *\frac{1}{2} } \\x=\frac{11}{\frac{\sqrt{2} }{4} } \\x=\frac{44}{\sqrt{2} }\\$

Then we rationalize

$x=22\sqrt{2}$

Hope you like it!

7 0

3 years ago

Read 2 more answers

Simplify the expression (m^3)^-1 (x^2)^5

Katyanochek1 [597]

(m^3)^-1 (x^2)^5 = (m^-3) (x^10) = x^10 / m^3

6 0

3 years ago