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slava [35]
3 years ago
15

PLEASE HELP ME OUT.

Mathematics
1 answer:
Ugo [173]3 years ago
5 0
First get into y-int form:
y=−<span><span>2x/</span>3</span>+<span><span>5/3
fill in y point:
</span></span>-3 = −<span>2/3(9) + b
b= 3
so
</span>y= −2/3(x) + 3
You might be interested in
Given a cylinder with a radius of 5cm and a height of 8 cm, find the volume of the cylinder. Use 3.14 for T.
Radda [10]

Answer: V=628cm³

Step-by-step explanation:

V=(3.14)r²h

V=(3.14)(5²)(8)

V=628cm²

Hope this helps! Have a great night!

6 0
2 years ago
Andrew purchased some drinks and some chips. Each bag of chips cost $2.00 and
skad [1K]

Answer:

2.5y=amount spent on drinks

Step-by-step explanation:

If chips are $2 and drinks are $2.50 and we do not know how many he bought of each, we put this into an equation which is

2x+2.5y

x=number of bags of chips while the 2 is two dollars per bag

so, if he bought 2 bags of chips 2(2)= $4 spent.

y= number of drinks and 2.5 is $2.5 per drink, so if he bought 4 drinks:

2.5(4)= $10 spent on drinks.

4 0
3 years ago
PLEASE HELP I WILL PICK BRAINLIEST
Mnenie [13.5K]

Answer:

A more complex question has rarely been asked.

Principia Mathematica took nearly a thousand pages to prove that 1+1=2. It does meander a bit, but had they wanted to prove 1+1=2 alone, it could have done so in 500 pages.

Mathematically speaking, the definition of 1 is:

There exists a number such that when multiplied upon an element of a specified set, yields the element of the specified set.

It is also defined as:

1.0000000000000000000000…

.9999999999999999999999999…

as the set of all singletons.

a singleton is a set with exactly 1 element.

These 4 definitions work in tandem with one another.

For example:

1=1

Divide both sides by 3.

1/3=1/3

Rewrite.

1/3=.33333333333333333...

Multiply both sides by 3.

1=.9999999999999999999...

Similarly:

If    =.9999999999999999999...

10=9.99999999999999999...

10=9+.99999999999999...

10=9+

Simplify by subtracting x from both sides.

9=9

=1

.99999999999999999999...=1

As the set of all singletons, 1 is also THE element that represents the set of all single entities.

That is to say: if you have 7 erasers. What you really have is a set of 7 single entities. The definition of 7 becomes: 1 + 1 + 1 + 1 + 1 + 1 + 1; and not as is commonly believed as: 6 + 1.

There is an argument for 7 to be defined as 6 + 1, but this argument is a corollary of the Peano Axioms which in turn argues that there exists a set with absolutely nothing in it {} and a set with exactly something in it {x}. More on this later.

The Principia Mathematica uses Peano's (from the Peano Axioms mentioned earlier) work and notation to expertly slice through the many nuances pertaining to this question.

This is something we will not do; but hopefully, we will also be able to effectively demonstrate why 1 + 1 = 2 in less than 1000 pages.

We will assume these basic principles of number theory:

There exists a number such that when multiplied to an element of a specific set, yields that element of the specific set.

There exists a number such that when added to an element of a specific set, yields that element of the specific set.

If we again assume to have only two sets, a set that is empty: {} containing no elements, and a set that is not empty {x} containing an element. We realize that Consequently, we went from nothing {}, to something {x}. This means that {x} is the successor to {}, as the next step up from nothing, is something.

As such we now have two elements:

Nothing, {}, and something that comes after {}, this something is called the successor, and it is the Successor of nothing.

in written notation we have:

{} and { the Successor of nothing }

Rewritten:

{0, the thing that comes after 0}

Further reworded:

{0, Successor (0) }

Reduced further:

0,(0)

Where S(0) stands in place of ‘the successor’. Further, we know there are an infinite number of possible Natural numbers, and we get:

{0, Successor of 0, the successor of the successor of 0, the successor of the successor of the successor of 0,…}

Further reduced:

0,(0),((0)),(((0))),((((0)))),(((((0)))),…

Further explained:

We know that we had nothing, and added something to it, and got something:

Nothing + Something = Successor of nothing.

0+__=(0)

We also know that there is nothing closer to 0, than the thing that comes after 0.

0+(0)=(0)

This implies that S(0) is the smallest increment possible from natural number to next natural number.

As a consequence, we now have two discovered entities: Something, and Nothing.

Let’s give them names.

We have decided that

Nothing = 0 .

0 = Nothing.

S(0) is the something that comes after nothing.

We define a new symbol: 1, to be: 1 = S(0)

This is to say that 1 IS the symbol that succeeds 0;

We could have drawn any shape to define the number that succeeds 0; we chose to draw a 1.

0+(0)=(0)

0+1=(0)

0+1=1

0,1,((0)),(((0))),((((0)))),(((((0)))),…

We now have definitions for 0, and 1. What about a definition for the thing that comes after one? The successor of 1?

As we know S(0) is the smallest increment available, and we are interested in finding S(0)’s successor we investigate:

The successor to the successor of Nothing:

0+(0)=1;1+(0)=(1)

This reads:

The successor of the successor of nothing IS the successor of one

And now… we need a new symbol.

We define the

(1)=2

The successor of 1 IS 2.

Thus:

0+(0)=1;1+(0)=(1)=2

Simplify:

0+1=1;1+1=(1);(1)=2.

Further:

0+1=1;1+1=2;2=2.

1 has many different properties; but all of the properties and their resulting definitions have little to do with why 1 + 1 = 2. And that 1 + 1 = 2 is a byproduct of properties inherent to Natural numbers.

Step-by-step explanation:

6 0
3 years ago
What is 122.18 rounded to the nearest whole number?
elixir [45]
The answer is 122 it’s basically the same rounding with whole numbers
6 0
2 years ago
The level of nitrogen oxides (NOX) in a exhaust of cars of a particular model varies normally with mean 0.25 grams per miles and
antoniya [11.8K]

Answer:

a) 15.87% probability that a single car of this model fails to meet the NOX requirement.

b) 2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

Step-by-step explanation:

We use the normal probability distribution and the central limit theorem to solve this question.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.25, \sigma = 0.05

a. What is the probability that a single car of this model fails to meet the NOX requirement?

Emissions higher than 0.3, which is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.3 - 0.25}{0.05}

Z = 1

Z = 1 has a pvalue of 0.8417.

1 - 0.8413 = 0.1587.

15.87% probability that a single car of this model fails to meet the NOX requirement.

b. A company has 4 cars of this model in its fleet. What is the probability that the average NOX level of these cars are above 0.3 g/mi limit?

Now we have n = 4, s = \frac{0.05}{\sqrt{4}} = 0.025

The probability is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3 - 0.25}{0.025}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

4 0
3 years ago
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