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3 years ago

Simplify: 8bc-9bc+10bc-6bc

Mathematics

2 answers:

jarptica [38.1K]3 years ago

6 0

3bc is the answer to your problem

ss7ja [257]3 years ago

6 0

Answer=

3bc

8-9+10-6=3

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3 years ago

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How many different types of cross sections of a cone are possible? A.3

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The answer is B. 5.
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3 years ago

Slove for X= what would this be for Mai poured 2.6 liters of water into a partially filled pitcher. The pitcher then contained 1

alexandr1967 [171]

Answer:

x + 2.6 = 10.4

x = 7.8

Step-by-step explanation:

If 2.6 liters are added to x liters with the result that 10.4 liters then exist, the model is ...

2.6 +x = 10.4 . . . . . . . 2.6 added to x gives 10.4

The commutative property of addition lets you rewrite this to ...

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2 years ago

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

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2 years ago

If elephant grass grows <br> 2 1/5 inches a day, how many inches will it grow in 6 days?

wel

Answer:

13.2 or 13 1/5 inches

Step-by-step explanation:

2 1/5 in/day * 6 days = 13.2 or 13 1/5 inches

2 1/5 in

+ 2 1/5 in

------------

13 1/5 in

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3 years ago