Question

Y= |x-1| and y=3x+2

Answer 1

Y = |x - 1|

and

y = 3x + 2

Equating the values of y, we can write:

|x - 1| = 3x + 2

This means:

A) x - 1 = 3x + 2 

x - 3x = 2 + 1 

-2x = 3
⇒ x = -3/2 = -1.5

B) - ( x - 1) = 3x + 2
3x + x = 1 - 2
4x = -1
⇒ x= -1/4 = - 0.25 

For x = -0.25
y = 3(-0.25) + 2 = 1.25

x = -1.5 is an extraneous root and is not applicable.

So the solution set is (-0.25, 1.25)

Option A gives the approximate solution set.

Answer 2

The answer is a A hope this would help you