Based on the given parameters, the value of the function h(-1) is -1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(-1)
This means that t = -1
So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1
h(-1) =-(-1)^2 + (-1) + 1
Evaluate the exponent
h(-1) =-1 - 1 + 1
Evaluate the like terms
h(-1) = -1
Hence, the value of the function h(-1) is -1
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(−1)
Answer:
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Step-by-step explanation:
BUT TRU UNFORINATLEY
Answer:
- using the rule given: 2.5
- using an exponential rule: 7
Step-by-step explanation:
Evaluating the linear rule given, for n = 1, we have ...
a1 = 7(1/2)(1) -1 = 7/2 -1 = 5/2 = 2.5
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We suspect you may intend the exponential function ...
an = 7(1/2)^(n-1)
Then, for n = 1, we have ...
a1 = 7(1/2)^(1 -1) = 7(1) = 7 . . . . the first term is 7
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When writing an exponential expression in plain text, it requires the exponential operator, a caret (^). If the exponent contains any arithmetic, as this one does, it must be enclosed in parentheses.
Answer:
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