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Pani-rosa [81]
4 years ago
13

Determine if the conclusion is valid or invalid based on the given information and explain your reasoning

Mathematics
1 answer:
mestny [16]4 years ago
4 0
Valid because it works in the given example
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H(t) = −t2 + t + 1 h(−1)
Gwar [14]

Based on the given parameters, the value of the function h(-1) is -1

<h3>How to evaluate the function?</h3>

The equation of the function is given as:

h(t) =-t^2 + t + 1

The function is given as:

h(-1)

This means that t = -1

So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1

h(-1) =-(-1)^2 + (-1) + 1

Evaluate the exponent

h(-1) =-1 - 1 + 1

Evaluate the like terms

h(-1) = -1

Hence, the value of the function h(-1) is -1

Read more about functions at:

brainly.com/question/1415456

#SPJ1

<u>Complete question</u>

Consider the following function definition, and calculate the value of the function

h(t) = −t2 + t + 1 h(−1)

6 0
2 years ago
So sad but so true do you think so ???
Inessa05 [86]

Answer:

AWWWWW :( SOOOOO SAD!!!

Step-by-step explanation:

BUT TRU UNFORINATLEY

6 0
3 years ago
Read 2 more answers
Given the rule: an=7(1/2)n-1 identify the first term
Shkiper50 [21]

Answer:

  • using the rule given: 2.5
  • using an exponential rule: 7

Step-by-step explanation:

Evaluating the linear rule given, for n = 1, we have ...

  a1 = 7(1/2)(1) -1 = 7/2 -1 = 5/2 = 2.5

_____

We suspect you may intend the exponential function ...

  an = 7(1/2)^(n-1)

Then, for n = 1, we have ...

  a1 = 7(1/2)^(1 -1) = 7(1) = 7 . . . . the first term is 7

_____

When writing an exponential expression in plain text, it requires the exponential operator, a caret (^). If the exponent contains any arithmetic, as this one does, it must be enclosed in parentheses.

3 0
4 years ago
Can I get help with this question?
juin [17]

Answer:

h well jskkkskwlejsjnekekwpwkqiwjeuehwiwnwoqmwlkwkwke just trying to get pinots. sorry

7 0
3 years ago
Read 2 more answers
Can someone help me out with number 2?
Norma-Jean [14]
\sin255^o=\sin(300^o-45^o)=\sin300^o\cos45^o-\cos300^o\sin45^o= \\\\=- \frac{ \sqrt{3} }{2}\cdot  \frac{ \sqrt{2} }{2}- \frac{1}{2} \cdot  \frac{ \sqrt{2} }{2}=-      \frac{ \sqrt{6} }{4} -  \frac{ \sqrt{2} }{4}=  -\frac{  \sqrt{6}+\sqrt{2} }{4}

5 0
4 years ago
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