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3 years ago

What is the area of the figure below? 7.5m^2 15m^2 21.25m^2 42.5m^2

Mathematics

2 answers:

Novay_Z [31]3 years ago

7 0

The answer is c!!! hope this helps!!!

Olenka [21]3 years ago

6 0

Answer:

Third option is correct. The area of figure is 21.25m^2.

Step-by-step explanation:

The area of a kite is

$A=\frac{1}{2}(d_1\times d_2)$

Both diagonals are perpendicular. Longer diagonal bisects the smaller diagonal.

In triangle ABO,

$\tan45^{\circ}=\frac{BO}{AO}$

$1=\frac{BO}{2.5}$

$2.5=BO$

The length of BD is

$BD=2\times BO=2\times 2.5=5$

The length of AC is

$6+2.5=8.5$

The area of kite ABCD is

$A=\frac{1}{2}(AC\times BD)$

$A=\frac{1}{2}(8.5\times 5)$

$A=21.25$

Therefore third option is correct. The area of figure is 21.25m^2.

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3 years ago

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A line passes through the points (2,4) and (5,6) .

Alenkinab [10]

Answer:

Option B and D are correct.

Step-by-step explanation:

Given: A line passes through the points (2,4) and (5,6).

* Case 1:

If a line passes through the points (2, 4) and (5, 6)

Point slope intercept form:

for any two points $(x_1,y_1)$ and $(x_2, y_2)$

then the general form $y -y_1=m(x-x_1)$ for linear equations where m is the slope given by:

$m =\frac{y_2-y_1}{x_2-x_1}$

First calculate slope for the points (2, 4) and (5, 6);

$m = \frac{y_2-y_1}{x_2-x_1} =\frac{6-4}{5-2} = \frac{2}{3}$

then, by point slope intercept form;

$y-4=\frac{2}{3}(x-2)$

* Case 2:

If a line passes through the points (5, 6) and (2, 4)

First calculate slope for the points (5, 6) and (2, 4);

$m = \frac{y_2-y_1}{x_2-x_1} =\frac{4-6}{2-5} = \frac{-2}{-3}= \frac{2}{3}$

then, by point slope intercept form;

$y-6=\frac{2}{3}(x-5)$

Yes, the only equation of line from the given options which describes the given line are;

$y-4=\frac{2}{3}(x-2)$ and $y-6=\frac{2}{3}(x-5)$

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4 years ago

Jamar's teacher told him that one of the reasons he gave on the proof below was incorrect. Which reason did he make the mistake

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Answer:

Reason given in step 2. is incorrect. It should read; "Distributive Property."

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3 years ago

What is the divisor of 2/7

olga2289 [7]

Answer:

the divisor is 7.

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3 years ago

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A circle with radius 9 has a sector with a central angle of 120°.

Vitek1552 [10]

120º is 1/3 of a complete revolution of 360º. So the area of this sector should be 1/3 the area of the complete circle.

A circle with radius 9 has area 9^2 π = 81π.

So the sector has area 81π/3.

Put another way: The area A of a circular sector and its central angle θ (in degrees) occur in the same ratio as the area of the entire circle with radius r according to

A / θ º = (π r ^2) / 360º

==> A = π/360 θ r ^2

In this case, r = 9 and θ = 120º, so

A = π/360 * 120 * 81 = 81π/3

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4 years ago