We know that tan²(A)+1 = sec²(A)--------> tan²(A)= sec²(A)-1 tan²(A)= (4/3)²-1------> tan²(A)=16/9-1-----> 7/9 tan²(A)=7/9 if the angle A is in the IV quadrant then tan (A) is negative therefore tan (A)=-√(7/9)-----> tan (A)=-√7/3 so cot (A)=1/tan(A)------> cot (A)=-3/√7----> -(3/7)*√7
the answers are a) the identity is tan²(A)= sec²(A)-1 b) tan (A)=-√7/3
It is a strangely worded question but you are dividing the paper in 3's n times so 3n will be part of the answer and you are dividing 200. So, the answer is 200/3n.
