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NemiM [27]
3 years ago
11

Help me with this problem I've been working on it for a while now and just can't figure it out

Mathematics
1 answer:
Serggg [28]3 years ago
7 0
1. Write out the problem: 3x+12/3

2. Find the common factor: 3(x+4)/3

3. Cancel out the threes.

4. Once you cancel them out you get: x+4

Hope I could help. Have a great day!:-)))
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What is the substitution of<br><img src="https://tex.z-dn.net/?f=%28x%20%20-%20%201%29%5E%7B2%7D%20" id="TexFormula1" title="(x
Ber [7]

Answer:

x should be 1

I think if you substitute it will just be the index 2 that remains , not sure though .You should probably ask your teacher for assistance

5 0
3 years ago
If f(x)=sinx−1/cos2x, then limx→π2f(x) is equivalent to which of the following?
Harrizon [31]

Answer:

2

Step-by-step explanation:

Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2

Substituting π/2 into the function

lim x-->π/2 sin(x)-1/cos 2(x)

= sin(π/2) - 1/cos(2)(π/2)

= 1 - 1/cosπ

= 1- 1/-1

= 1 -(-1)

= 1+1

= 2

Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2

8 0
3 years ago
Can you please help me
Igoryamba

Answer:

30 inches

Step-by-step explanation:

8 0
3 years ago
Problem Solving each problem by solving a simpler problem. solve There are two identical figures with all sides of equal length.
PolarNik [594]
Pentagon and each side is 2 units
3 0
3 years ago
The explicit rule for a sequence is given. an=4n−1 What is the recursive rule for the sequence?
Gnom [1K]

Answer:

a_{n+1}=a_n+4

Step-by-step explanation:

Have in mind the definition of the term a_n=4\,n-1, and now work on what the term a_{n+1} is based on the previous definition:

a_{n+1} = 4\,(n+1)-1\\a_{n+1}=4\,n+4-1

In the next step do NOT combine the numerical values, but try to identify the a_n term (4\,n-1) in the expression (notice the use of square brackets to group the relevant terms):

a_{n+1}=4\,n+4-1\\a_{n+1}=[4\,n-1]+4\\a_{n+1}=a_n+4

So now we have the term "a_{n+1}" defined in a recursive manner based on the previous term "a_n"

8 0
3 years ago
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