The probability that Aiden randomly selects an oatmeal cookie from the bag, eats it, then randomly selects a chocolate chip cookie is 0.0721
<h3>How to determine the probability?</h3>
The distribution of the cookies is given as:
- 9 chocolate chip cookies
- 8 peanut butter cookies
- 8 sugar cookies
- 9 oatmeal cookies
When he eats a cookie, the number of cookies reduces by 1
So, the required probability is:
P(Oatmeal and Chocolate) = Oatmeal/Total * Chocolate/Total - 1
This gives
P(Oatmeal and Chocolate) = 9/(9 + 8 + 8 + 9) * 9/(9 + 8 + 8 + 9 -1)
Evaluate
P(Oatmeal and Chocolate) = 0.0721
Hence, the probability is 0.0721
Read more about probability at:
brainly.com/question/25870256
#SPJ1
Answer:
It is C.
Step-by-step explanation:
If you multiply 21 by 2 you will get, 42. If you add 16 to 42 it will equal 58. your welcome:)
Since both of the equations are equal to y...set them equal to each other.. So it will then be
x^2+3=x+5
-3 -3
x^2=x+2 ---> x^2-x-2
(x-2) (x+1)
x=2,-1
-29
-5(6) + 1
-30 + 1
-29
hope this helps !
