In an arithmetic sequence, the difference between consecutive terms is constant. In formulas, there exists a number
such that
![a_{n+1}-a_n=r\quad \forall n\geq 1](https://tex.z-dn.net/?f=a_%7Bn%2B1%7D-a_n%3Dr%5Cquad%20%5Cforall%20n%5Cgeq%201)
In an geometric sequence, the ratio between consecutive terms is constant. In formulas, there exists a number
such that
![\dfrac{a_{n+1}}{a_n}=r\quad \forall n\geq 1](https://tex.z-dn.net/?f=%5Cdfrac%7Ba_%7Bn%2B1%7D%7D%7Ba_n%7D%3Dr%5Cquad%20%5Cforall%20n%5Cgeq%201)
So, there exists infinite sequences that are not arithmetic nor geometric. Simply choose a sequence where neither the difference nor the ratio between consecutive terms is constant.
For example, any sequence starting with
![1, 15, -3,\ldots](https://tex.z-dn.net/?f=1%2C%2015%2C%20-3%2C%5Cldots)
Won't be arithmetic nor geometric. It's not arithmetic (no matter how you continue it, indefinitely), because the difference between the first two numbers is 14, and between the second and the third is -18, and thus it's not constant. It's not geometric either, because the ratio between the first two numbers is 15, and between the second and the third is -1/5, and thus it's not constant.
The answer is 15 !
Explanation:
You have 15 slots, each of which will hold one of the names of the players. You need to fill the first slot with some name.
The answer is c 10 #s are greater than 110
Answer:
c(12 + 9 + 6)
12(2.25c)
Step-by-step explanation:
12c + 12 (3/4c) + 12 (1/2c)
12(1c) + 12(3/4c) + 12 (1/2c)
12(c + 3/4c + 1/2c)
12(2 1/4c)
12(2.25c)
Or
12c + 12 (3/4c) + 12 (1/2c)
12c + 9c + 6c
c(12 + 9 + 6)
Answer:
Valerie can cut 13 2/3 ft pieces.
Step-by-step explanation:
Please brainliest!