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Snezhnost [94]
4 years ago
14

Given JAM an segment PB such that PB || JM what is the missing justification in the proof that JP/PA=MB/BA

Mathematics
2 answers:
elena-14-01-66 [18.8K]4 years ago
5 0
The answer is c. corresponding angles are congruent
vovangra [49]4 years ago
4 0

When two lines are crossed by another line the angles in matching corners are called Corresponding Angles .When the two lines being crossed are Parallel Lines the Corresponding Angles are equal.

In the figure given PB || JM .

We need to write the reason for statement <AJM is congruent to <APB.

These angles are on matching corners for the parallel lines PB&JM so they are corresponding angles.

Option C. Corresponding angles are congruent  is the right justification for the given statement.

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Answer:

This is a function because each x value has a different y value. If one of x values would of had two different y values then it would of not have been  a function

Step-by-step explanation:

6 0
3 years ago
In a crayon box there are 5 dark colors for every 8 light colors. If there are 20 dark colors, how many light colors are there.
Alex17521 [72]

Answer:32

Step-by-step explanation:

Since 5 dark colors are equal to 8 light colors, see how many times 5 goes into 20. 20/5=4. So now multiply 8 with 4. 8x4=32.

4 0
3 years ago
Find the slope of the line containing the pair of points.<br> (-10,6) and (-11,7)
denis-greek [22]

Answer:

Step-by-step explanation:

(-10,6)(-11,7)

Slope is -1

6 0
3 years ago
Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

4 0
3 years ago
Here is 19 and 20 thank yall
Veseljchak [2.6K]

Answer:

19: The difference between the temperature in Fair Banks and Barlow is 3°F

20: -13°F, -10°F, 15°F, 24°F.

Step-by-step explanation:

I'm assuming that by "compare", it means to find the difference between temperatures in question 19. If it means something else, let me know and I'll try and help you find it.

4 0
3 years ago
Read 2 more answers
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