3x -1 = 11
3x = 11 + 1
3x = 12
x = 4
I take it by, x2 + x, you mean 2x + x, since x = 4, then
2x + x = 2(4) + (4) = 8 + 4 =12
Using the normal distribution, it is found that Sue will get a letter grade of B.
In a <em>normal distribution </em>with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, Sue got a grade of 0.85, hence 
.
- Looking at the z-table, z = 0.85 has a p-value of 0.8023, hence she is approximately in the top 20%, which is below the top 15% but above the top 50%, hence she got a letter grade of B.
A similar problem is given at brainly.com/question/25745464
X time 0.8 (or 80 percent)= 15
so 15/0.8=X
18.75
Answer:
(i) 7/10
(ii) 3/10
(iii) 1/5
(iv) Rs 40,000
Step-by-step explanation:
The fraction of the salary spent on food = 1/2
The fraction of the salary spent on rented house fee = 1/5
(i) The fraction spent for both food and rental fee = (1/2) + (1/5) = (5 + 2)/10 = 7/10
(ii) The remainder (rest) of the salary = 1 - 7/10 = 3/10
The fraction of the remainder spent for children's education = 1/3
The fraction of the total salary spent for the children's education = (1/3) × (3/10) = 1/10
(iii) The remaining portion deposited in the bank = 1 - (1/10 + 7/10)) = 2/10 = 1/5
(iv) The amount equal to portion of 1/5 of his salary deposited in the bank is Rs 8000
Let <em>x</em> represent his whole salary, we have;
(1/5) × x = Rs 8,000
x = 5 × Rs 8,000 = Rs 40,000
His whole salary is Rs 40,000.
