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Likurg_2 [28]
2 years ago
13

James bakes 12 cookies in 15 minutes. How many cookies will he bake in 60 minutes?

Mathematics
2 answers:
finlep [7]2 years ago
8 0

Answer:

48 :D

Step-by-step explanation:

vlabodo [156]2 years ago
6 0

Answer: James will bake 48 cookies.

Step-by-step explanation:

We know that James can bake 12 cookies in 15 minutes. So, we can multiply both amounts ( the amount of cookies and the minutes it takes) to solve this question. First, ask " How many 15 minutes are in 60 minutes?" Or, 15 multiplied by what makes 60? The answer to this is 4. 15 minutes x 4= 60 minutes. Now, all we have to do is multiply the other side by the same amount. 12 cookies x 4 =48 cookies. So, he bakes 48 cookies.

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If you’re trying to find x, x = 3.
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3 years ago
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VMariaS [17]
From order of operations, we do multiply/divide first, then add/subtract. So:
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3 0
3 years ago
The density of a certain material is such that it weighs 6 pounds per pint of volume.
ella [17]

Answer:

Density = 5751.66 gram per litre

Step-by-step explanation:

It is given that the density of a certain material 6 pounds per pint.

The conversion from pint to liter is as follows :

1 pint = 0.473 litre

The conversion from pounds to kg is as follows :

1 pound = 453.59 kg

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So,

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3 0
3 years ago
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u &gt; 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

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3 years ago
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Answer:

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Step-by-step explanation:

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