Hello
f(x) = 2sin(x)
f(<span>π/6) = 1
f'(x) 2cos(x)
f'(</span>π/6) = 2×co(π/6) = 2 × root(3)×0.5 =root(3)
The equation of this tangent line is : y= root(3)(x-π/6)+1
y = root(3)x+1 - π/6(root(x)) <span>in the form y=mx+b
m = root(3) and b = </span>1 - π/6(root(x))
Answer:
(D) 2√3
Step-by-step explanation:
From the above question ,we are asked to solve for:
6/√12 −√3
In other to simplify, we would expand the numerator of 6/√12
So we have;
= [6/(√4 ×√3)] - √3
= (6/ 2 ×√3) - √3
= (6/2 × √3) - √3
= (3 ×√3) - √3
= 3√3 - √3
= 2√3
Therefore, the value of 6/√12 −√3 is
option (D) 2√3
Answer:
A (c=1,900-163-259)
Step-by-step explanation:
This is right because this equation follows the PEMDAS rules in order to get the correct answer.
We are given f(x) =3x and g(x) =2x
Now we have to find (g*f)(x).
so (g*f)(x) means we multiply f(x) and g(x).
So multiplying 3x and 2x,
3x * 2x = 6x²
So (g*f)(x) =6x²
