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4 years ago

5

there are 1001 pennies in a line i change every second pennie with a nickel i change every third pennie with a dime and i change

every fourth pennie with a quarter how much money do i have

1 answer:

Dvinal [7]4 years ago

4 0

1001/2=? $ 0.05(x)
1001/3=? $ 0.10(x)
1001/4=? +$ 0.25(x)
_______

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Twenty words were randomly selected from two textbooks. Each set gives the number of letters in each of the twenty words for tha

Alborosie

Answer:

k = 13The smallest zero or root is x = -10

Step-by-step explanation:

you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

7 0

3 years ago

Write 4.83…. (The 3 repeats infinitely)as a mixed number

kogti [31]

Answer:

$4\frac56$

Step-by-step explanation:

$\frac56=0.8 \dot{3}$

$\implies 4.8 \dot{3}=4\frac56$

6 0

2 years ago

Read 2 more answers

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$

So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067$

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is made

c) What is the probability that seven people make a purchase in the next four minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

$\mu = 4*5 = 20$

We have to find P(X = 7).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005$

0.05% probability that seven people make a purchase in the next four minutes

8 0

4 years ago

A single numerical value used as an estimate of a population parameter is known as

suter [353]

A point estimate, I believe

4 0

3 years ago

At Mr. Neely bank, the interest rate offered to clients is 4.5% annually. If after three years at the bank he has earned $50 in

tangare [24]

Answer: 9 dollars.

Step-by-step explanation: Just do 4.5/50 x 100 also could I get brainest?

6 0

3 years ago

Read 2 more answers