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Mkey [24]
3 years ago
7

How many numbers can you make with four digits

Mathematics
2 answers:
kap26 [50]3 years ago
8 0
You can make a lot of numbers as long as there are four digits!
Natasha_Volkova [10]3 years ago
5 0
Well, first consider how many digits there are. You have 1, 2, 3, 4, 5, 6, 7, 8, 9, and 0, depending on how you use it, that are all digits.
If you count 0 as a digit other than a place holder (0000, 0001, etc.), you would end up with ten thousand (10,000) numbers with four digits, starting with 0000, and ending with 9999. If you count 0 as nothing other than a place holder (1000, 1001, etc.), you would have nine thousand (9,000) numbers with four digits, starting with 1000.
So, depending on how you view 0, you can make up to 10,000 different numbers that contain four digits.
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Harlamova29_29 [7]

Answer:

4/1/7 ( 4 and 1 over 7)

Step-by-step explanation:

First add all the numbers

1+2+3+4+5+6+8= 29

Finally you divide the total by counting the numbers which you have add up

29÷7

= 4/1/7 ( 4 and 1 over 7)

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3 years ago
What is the LCD of 3/5 and 1/6
Jobisdone [24]

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3 years ago
Which coordinate (g, z) lies in the solution set for the following system of inequalities?
geniusboy [140]

Answer:

B. (6, 1)

Step-by-step explanation:

A graph of the solution space shows that the point (6, 1) is the only one that satisfies both inequalities.

___

<em>Verification</em>

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3(6) -4(1) = 18 -4 = 14 > 12

_____

<em>Notes on the Solution</em>

The graphing calculator used here only recognizes variables x and y. Since g is the first variable in the ordered pair (g, z) we use x to represent g in the equations that are graphed. Similarly, y is used to represent z in the graphed equations.

You graph an inequality by graphing it as though it were an equation, then choosing the appropriate half-plane (one side of the line or the other) to shade as the solution space. Where the shadings from the two inequalities overlap, both are satisfied by points in that area.

In the first inequality, x and y values that are less than those on the line will satisfy the inequality, so the shading is below the line.

In the second inequality, x values greater than those on the line will satisfy the inequality, so the shading is to the right of the line.

In both cases, the line is graphed as a dashed line. This is because the points on the line do not satisfy the < or > conditions, so are not part of the solution set. (If one or both conditions were ≤ or ≥, then the corresponding line would be solid, and the points on the line would be part of the solution.)

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3 years ago
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Answer:

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