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Varvara68 [4.7K]
3 years ago
5

What is the percent of change to 125 centimeteres 87.5 centimeters?

Mathematics
1 answer:
MrRa [10]3 years ago
5 0
I hope this helps you

125-87,5=37,5

125 37,5

100 ?

?.125=100.37,5

?=3750/125

?=30


30%
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Please help me urgently! 50 points giving brainliest.
Alisiya [41]

The number of significant figures in the numbers are

  • 100 cm = 1 significant digit
  • 0.006700 cm = 2 significant digits
  • 450. cm = 3 significant digits

<h3>How to determine the number of significant figures in the following numbers?</h3>

As a general rule, the zeros before and after the non-zero figures are not significant.

Using the above rule, we have:

  • 100 cm = 1 significant digit
  • 0.006700 cm = 2 significant digits
  • 450. cm = 3 significant digits

<h3>How to round the following numbers to the correct number of significant figures</h3>

Using the above rule in (a), we have:

  • 123g to show 1 sig fig = 100 g
  • 0.19851m to show 2 sig figs = 0.2 m
  • 0.0057034L to show 3 sig figs = 0.005703 L

<h3>How to report the following answers with correct significant figures</h3>

We have:

(12.93cm) x (2.34cm) x (8cm) = 242.05 cm^3 because 12.93 has 4 significant figures

67.0m / 2.18s = 30.7 m/s because 2.18 has 3 significant figures

<h3>How to convert the following metric to metric</h3>

450mL = 0.45 L

because 1 mL = 0.001 L

2.3 dm = 0.00023 km

because 1 dm = 0.0001 km

0.120cg = 1.2 mg

because 1 cg = 10 mg

6700L = 670000 cL

because 1 L = 100 cL

<h3>How to convert the following metric</h3>

a. 2.34miles = 3.76 km (1mile = 1.61km) -- given

b. 5.3ft = 161.544 cm(2.54cm = 1 in)

Because 1 ft = 30.48 cm

Read more about significant figures at:

brainly.com/question/24491627

#SPJ1

3 0
2 years ago
The spray from a sprinkler reaches 21 feet from the sprinkler and creates a circle as it spins. What is the
mylen [45]

Answer:

66ft

Step-by-step explanation:

c=pixD

c=pix21

c=65.9...=66ft

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3 years ago
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9.50 One way to evaluate the effectiveness of a teaching assistant is to examine the scores achieved by his or her students on a
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Answer:

Step-by-step explanation:

Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.

H_0: s^2 = 300\\H_a: s^2 \neq 300

(Two tailed test for variance )

Sample variance =480

We can use chi square test for testing of hypothesis

Test statistic = \frac{(n-1)s^2}{\sigma^2} \\=62.4

p value = 0.0100

Since p <0.05 our significance level, we reject H0.

The sample variance cannot be claimed as equal to 300.

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3 years ago
9, 21, 7, 11, 13, 21, 5, 14, whats the range?
maria [59]
16 would be the range. The lowest value is 5, and the highest value is 21. You just subtract those two which gives you 16! (:
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