c is correct.
(Pe)²/(De)³=(Pj)²/(Dj)³ (Pe stands for period of Earth, De for Distance of Earth from Sun,
Because Dj=5.2De
(Pe)²/(De)³=(Pj)²/(5.2De)³
Pj=√(5.2³)(Pe)²=(5.2³)(1)² ≈11.9 =(note: Pe=1 earth year)
Answer:
Therefore the Area of Rhombus ABCD is 36 unit².
Step-by-step explanation:
Given:
ABCD is a Rhombus
A = (-1,0)
B = (5,-3)
C = (-1,-6)
D = (-7 ,-3)
To Find:
Area of Rhombus ABCD = ?
Solution:
We know that Area of Rhombus is given as

Where ,
d₁ and d₂ are the Diagonals.
We have,
Diagonals as AC and BD,
Using Distance Formula we get

Substituting coordinates A and C we get

Similarly for BD we have,

Now Substituting AC and BD in Formula we get


Therefore the Area of Rhombus ABCD is 36 unit².
Answer:
Step-by-step explanation:
No.3
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