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Rus_ich [418]
3 years ago
10

Help with 2 and 3 Please help

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0
2. Some fractions could be different in denominator and numerator so you'll have to make all denominators the same in order to order them. It'll make it easier because the numerator will show which numbers are greater than the other. For example, 1/2 and 3/4, u could convert both to equivalent fractions. Make 1/2 into 2/4 and 3/4 stays the same, 3/4 is greater than 2/4 so it goes first.

3. 2/3, 7/12, 4/9, 1/2, 3/8, 5/24.
It's in this order because their equivalent fractions are,
27/72, 48/72, 36/72, 42/72, 36/72, 15/72.( that's the order they're in in the question)
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4 0
3 years ago
Work out <br>a. 5 x 1/8<br><br>b.1/7 x 6 <br><br><br>plzz help ​
yan [13]

Answer:

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8 0
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Step-by-step explanation:

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8 0
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Read 2 more answers
One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
4 years ago
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