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yan [13]
4 years ago
7

To join a local square dancing group Jane has to pay $100 sign up fee plus $25 per month write an equation for the cost (y) base

d on the number per months(x)
Mathematics
1 answer:
ollegr [7]4 years ago
6 0
The equation is 100 + 25x = y. Do you want the answer too?
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A one-parameter family of solutions of the de p' = p(1 − p) is given below.
tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when c_{1} = -\frac{4}{3}.

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

4 = \frac{c_{1}}{1 + c_{1}}

4 + 4c_{1} = c_{1}

c_{1} = -\frac{4}{3}

A solution curve pass through the point (0,4) when c_{1} = -\frac{4}{3}.

Through the point (0, 1)?

Same thing as above

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

1 = \frac{c_{1}}{1 + c_{1}}

1 + c_{1} = c_{1}

0c_{1} = 1

No solution.

So there is not a solution curve passing through the point(0,1).

3 0
3 years ago
Help.........................<br><br>​
garri49 [273]
<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

7 0
3 years ago
An aircraft has a maximum of 30 first class seats and 220 economy seats.
guajiro [1.7K]

Answer:

x<y first inequality

x>y second inequality

x=y third inequality

5 0
4 years ago
Find the value of x. 1/2 - 15 = 2/5x - 7​
Dmitrij [34]

Answer:

the answer is 80

Step-by-step explanation:

hope this helps

can i get braineist pls

6 0
3 years ago
Read 2 more answers
I have 30 ones 2thousands 4hundred thousands , 60 tens and 100 hundreds what number am I ?
viva [34]

Answer:

Step-by-step explanation:

Units = 30

Thousands = 2,000

Hundreds of Thousands = 400,000

Tens = 60

Hundreds = 100

HTHHTU

400,000

    2,000

       100

         60

<u>          30</u>

<u>402,190</u>

7 0
4 years ago
Read 2 more answers
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