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3 years ago

Please solve the equations below. Explain. 3x-4=x 2x-4=x

2 answers:

7 0

10Step 1: Subtract x from both sides.3x−4−x=x−x2x−4=0Step 2: Add 4 to both sides.2x−4+4=0+42x=4Step 3: Divide both sides by 2.2x2=42x=2

2)Step 1: Subtract x from both sides.2x−4−x=x−xx−4=0Step 2: Add 4 to both sides.x−4+4=0+4x=4

igomit [66]3 years ago

5 0

Well, lets solve by combing like terms.
For the first it would be:
2x=4
The second would be:
x=4
So for #1 x=2 and #2 x=4

Hope this helps!

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8 grams = milligrams

Digiron [165]

Answer:

8,000 miligrams

Step-by-step explanation:

There's 1000 milligrams in a gram so you would have to do multiplication.

which if you do..

8x1000

you should get...

8000 milligrams

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3 years ago

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mariarad [96]

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3 years ago

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Mrs. Olive used 1 2/5 quarts of syrup and 5 3/10 quarts of water to make lemonade. How many quarts of lemonade did she make? * A

Flura [38]

Answer:

B. 6 7/10

Step-by-step explanation:

We solve the above y by carrying out addition.

The quarts of Lemonade she made is calculated as:

1 2/5 quarts of syrup + 5 3/10 quarts of water

= 1 + 5 + (2/5 + 3/10)

Lowest common denominator = 10

= 6 ( 4 + 3/10)

= 6 7/10 quarts of Lemonade

Mrs Olive made 6 7/10 quarts of Lemonade

3 0

3 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .